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3 years ago

Can you please answer the question in the picture ! :)

Computers and Technology

1 answer:

Ilya [14]3 years ago

4 0

Answer:

Explanation: If and else statements are one of the most important parts of programming.

1. You add an if you do something if a condition is met. For example, if number of chocolates equals zero( a condition), and inside you can do something like buy more chocolates. And else statement happens if the if condition isn't met and you want to the code to do something else. You don't need this if you don't want anything to happen if the if condition isn't true.

2. This might be used in a number guessing game. Let's say you have to guess a number, if its correct the computer should correct but if you get it wrong it should display wrong. You can write if the number the user writes in equal to the number you are supposed to guess say correct. Else say wrong

Hope this helps. Please mark as brainliest! Thanks!

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1. What are the advantages and disadvantages of technology in communication?

Gennadij [26K]

Answer:

ADVANTAGES:

First, the evolution of technology is beneficial to humans for several reasons. At the medical level, technology can help treat more sick people and consequently save many lives and combat very harmful viruses and bacteria.

2-Technology has also increased the productivity of almost every industry in the world. Thanks to technology, we can even pay with bitcoins instead of using banks

DISADVANTAGES:

1-Lack of Privacy. You might think that a quick text or IM offers more privacy than a telephone call in a crowded room. ...

2-Distraction from Real Life. ...

3-Potential for Misunderstanding. ...

4-Decline of Grammar and Spelling...

5- Near people are far and far people are near through communication technology. we have no time to sit with our relatives but constantly communicate far away people . I think this is biggest <em>disadvantage </em>

Explanation:

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3 years ago

Read 2 more answers

Sam has created a fashion website. There are many subscribers to his website. He has added new blogs, pictures, and articles abo

marusya05 [52]

Answer:

Post advertisements on social media and message the subscribers.

Explanation:

There is no point in not promoting and putting forward the work that he has been doing. All of the given options are about promoting the content but Sam needs to choose the ones which are efficient and seem professional as well.

Posting advertisements about the website promotes the content on a wider base and helps in luring more and more people to the website.

Messaging or sending an email to the subscribers is a healthy of letting the subscribers about the updates and latest posts.

8 0

3 years ago

The network of safe houses that assisted runaway enslaved people was known as:.

dedylja [7]

Answer:

The Underground Railroad

Explanation:

4 0

2 years ago

Write the following program in C++ to print:

Alenkinab [10]

1.
#include <iostream>#include <string>
using namespace std;
int main(){ string chars; // This is where we will put our @ signs and print them for(int x=0;x < 5; x++){
chars = chars + '@'; // This will concatenate an @ sign at the end of the variable cout << chars << "\n"; }}

2.
#include <iostream>#include <string>
using namespace std;
int main(){ string name; // Our variable to store the name cout << "What is your name? \n"; // Asks the user for their name cin >> name; cout << "\nWell, hello " << name << "!";}

3.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; // Asks for a number cin >> number; cout << "You entered " << number << "%!";}

4.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; cin >> number;
int check = number % 2; // The modulo operator (the percent sign) gets the remainder of the quotient if (check == 0) { cout << number << " is even!"; // If the remainder is 0 then it prints out "x is even" } else { cout << number << " is odd!"; // If the remainder is not 0 then it prints out "x is odd" }}

5.
#include <iostream>#include <string>
using namespace std;
int main(){ float r; // Our variable cout << "Enter a radius\n"; cin >> r; if (r < 0){ cout << "Lol. No."; // If the radius is less than zero print out that message } float circumference=2*3.14*r; float area=r*r*3.14; cout << "\n\n Circumference of circle: " << circumference; cout << "\n Area of circle: " << area;}

4 0

3 years ago

5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S

Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0

2 years ago