As long as Loren drove, the law of motion was
As long as Loid drove, the law of motion was
So, the total time they took is
Had Loren driven the whole time, the law of motion would have been
And we know that this time would have been 30 minutes (i.e. 0.5 hours) faster. So, we have
This translates into
If we subtract 200/s from both sides, we have
We can simplify the right hand side by summing the two fractions:
So, we have to solve
If we cross multiply the denominators, we have
Which yields the solutions
We accept the positive solution, because the negative would mean to travel backwards, so Loren's rate was 50mph
Answer:
Durante el frente frío mencionado en el ejercicio, la temperatura de Canadá bajó:
Step-by-step explanation:
Para obtener la cantidad de grados que bajó la temperatura en el caso mencionado, debes primero identificar la disminución en los grados positivos, es decir, cuando los grados Celsius llegaron a 0°C:
- Diferencia entre 7°C y 0°C = <u>7°C</u>
En la operación matemática, solo restante la cantidad de grados necesarios a la temperatura inicial (7°C) para que la temperatura quedara en 0°C, donde obtenemos una diferencia de 7°C, ahora identificas la cantidad de grados que se necesitan para que la temperatura pase de 0°C a -5°C:
- Diferencia entre 0°C y -5°C = <u>5°C</u>
Recuerda que como ya estamos hablando de diferencia, no necesitas señalar si los grados son negativos, solo identificamos el número de grados Celsius entre esas temperaturas mencionadas, por lo tanto, al final sumas las dos diferencias halladas y esa será la diferencia total entre las dos temperaturas dadas:
- Diferencia entre 7°C y -5°C = 7°C + 5°C
- <u>Diferencia entre 7°C y -5°C = 12°C</u>
Por lo tanto, durante el frente frío mencionado, <em><u>la temperatura en Canadá bajó 12°C</u></em>.
Answer:
Step-by-step explanation:
Formulas used:
Given :
LHS =
U have a slope of 2...and ur y int is the origin (0,0)
so ur equation is : y = 2x
Answer:
Ratios can be divided into part-to-part ratios and part-to-whole ratios. Part-to-part ratios provide the relationship between two distinct groups.Part-to-whole ratios provide the relationship between a particular group and the whole populations (including the particular group). For example, 3/5 of the students in the class are girls, or the mixture is 40% rye grass (40% is equivalent to saying 40 of every 100 parts).
Step-by-step explanation: