Answer:
The height of the tree = 25 feet
Step-by-step explanation:
From the given diagram : EF = 5 feet, FA = 8 feet, CA = 40 feet
∠AFE = 90° and ∠ACB = 90°
To find : CB, the height of the tree.
Solution : In ΔAEF and ΔAB C
∠AFE = ∠ACB = 90°
∠A is common angle.
So, By AA postulate of similarity of triangle, ΔAEF ~ ΔABC
Now, sides of similar triangles are proportional to each other

Hence, The height of the tree = 25 feet
Answer:
$(159+x)
Step-by-step explanation:
Given
Discount price = $x
Amount Emma paid after discount = $159
Original price = Amount paid + Discount
Original price= $159 + $x
Hence the required expression is $(159+x)
Answer:
ITS C THE ANSWER IS C
Step-by-step explanation:
Answer: The test statistic is t= -0.90.
Step-by-step explanation:
Since we have given that
n₁ = 50
n₂ = 25

So, s would be

So, the value of test statistic would be

Hence, the test statistic is t= -0.90.