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Iteru [2.4K]
3 years ago
10

Five students participated in an Easter egg hunt. Ally snatched up one

Mathematics
1 answer:
babunello [35]3 years ago
4 0

Answer:

There were a total of 72 Easter eggs.

Step-by-step explanation:

Since five students participated in an Easter egg hunt, where Ally snatched up one quarter of all of the eggs, Brett only managed to get half of what Ally found, Lee snagged six more than Brett, Jen ended up with half of Lee's take, While Lisa snagged three times that, to determine how many eggs were there in total, the following calculation must be performed:

Ally: 0.25X

Brett: 0.125X

Read: 0.125X + 6

Jen: 0.0625X + 3

Smooth: 0.1875X + 9

X - 0.25X - 0.125X - 0.125X - 0.0625X - 0.1875X = 0.25

0.25X = 6 + 3 + 9

0.25X = 18

Ally: 18

Brett: 9

Read: 15

Jen: 7.5

Smooth: 22.5

18 + 9 + 15 + 7.5 + 22.5 = X

72 = X

Thus, there were a total of 72 Easter eggs.

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3 0
3 years ago
Help please! show work
e-lub [12.9K]
Your answers are
A = 35.7°
B = 67.6°
C = 76.7°

cosine law

a^2 = b^2 + c^2 -2bc \cos A \\&#10;-2bc \cos A = a^2 - b^2 - c^2 \\ \\&#10;\cos A = \dfrac{a^2 - b^2 - c^2}{-2bc} \\ \\&#10;A = \cos^{-1}\left[ \dfrac{a^2 - b^2 - c^2}{-2bc} \right] \\ \\&#10;A = \cos^{-1}\left[ \dfrac{12^2 - 19^2 - 20^2}{-2(19)(20)} \right]  \\ \\&#10;A = 35.723697

A = 35.723697
sine law for the rest of the angles

\displaystyle&#10;\frac{\sin B}{b} = \frac{\sin A}{a} \\ \\&#10;\sin B = \frac{b \sin A}{a} \\ \\&#10;B = \sin^{-1} \left[ \frac{b \sin A}{a}  \right] \\ \\&#10;B = \sin^{-1} \left[ \frac{19 \sin 35.723697 }{12}  \right]  \\ \\&#10;B \approx 67.58886795

B = 67.58886795
All angles in triangle sum to 180 so find C with that

A + B + C = 180
C = 180 - A - B
C = 180 - 35.723697 - 67.58886795
C = 76.7°

7 0
3 years ago
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