gracie and mary and nancy each have a small collection of seashells gracie has 5 more than 1 and 1/4 times the number of shells
mary has. nancy bas 1 more than 1 and 1/2 the number of shells mary has. if gracjr and nancy have the same number of shells if x is the number of shells mary has identify the equation that represents this situation and identify its solution
X = mary's shells g = 1 1/4x + 5 n = 1 1/2x+ 1 g = n
1 1/4x + 5 = 1 1/2x + 1 5/4x + 5 = 3/2x + 1...multiply by common denominator of 4, this will get rid of fractions...however, this is optional...u can work with fractions if u wish. 5x + 20 = 6x + 4 5x - 6x = 4 - 20 -x = - 16 x = 16....so Mary has 16 shells
(s o t)(x)=s(t(x)) (s o t)(-7)=s(t(-7)) x=-7→t(-7)=3(-7)→t(-7)=-21 (s o t)(-7)=s(t(-7))=s(-21) x=-21→s(-21)=2-(-21)^2=2-441→s(-21)=-439 (s o t)(-7)=s(t(-7))=s(-21)=-439 Answer: Option A -439