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Ierofanga [76]
3 years ago
13

The graph of a quadratic equation opens down when the value of is negative.

Mathematics
1 answer:
motikmotik3 years ago
6 0

Answer:

given a quadratic function, y = ax2 + bx + c, when "a" is positive, the parabola opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value

Step-by-step explanation:

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Find the missing term and the missing coefficient 6a −( )5a =( ) a2 − 35a
andrew11 [14]
Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
 Let the missing term be X
 Let the missing coefficient be Y
 Therefore, (6a – X)5a = Y(a^2) – 35a
 6a x 5a – X.5a = Y.a^2 – 35a
 30a^2 – X.5a = Y.a^2 – 35a
  Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
 30 = Y; 5X = 35
Y = 30; X = 7
   Therefore, (6a-7)5a = 30 a^2 – 35a <span>
</span>
3 0
3 years ago
Mr. Vogel is riding the stationary bike at the gym. He completes 41 1/2 wheel rotations even 1/3 minute. what Mr Vogel's unit ra
Eva8 [605]
1/3times3=3/3 3/3 is the same as a whole so do 41 and 1/2 times 3 this gets you an answer of 124.5 meaning the unit 124.5x he makes 124.5 rotations per minute
4 0
3 years ago
A single little brown bat can eat up to 1,000 mosquitoes in a single hour. Express in scientific notation how many mosquitoes a
Nastasia [14]
Our final answer must represent "number of mosquitos."  This verifies that the correct calculation would be

1000 mosquitos              10.5 hours
-----------------------  x   --------------------
         1 hour                           1

Multiply this out.  Note that "hours" will cancel.

Whats your result?

Supposing that your result looked like   xxxxx times 10^0,

you'd convert this into scientific notation by moving the decimal place four units to the left (obtaining x.xxx) and then increasing the exponent of 10 from zero to four (obtaining 10^4).

Then your answer would have the form x.xxx times 10^4 (mosquitos)
8 0
3 years ago
I need help on this. I've no idea about this. Please help me...​
Mashcka [7]

Answer:

Answers are below.

Step-by-step explanation:

Hope this helps:)

4 0
2 years ago
At a farm, there are two huge pits for storing hay. 90 tons of hay is stored in the first pit, 75 tons in the second pit. Then,
Travka [436]

Answer:

63 tons

Step-by-step explanation:

The problem statement asks for the tons of hay removed from the first pit. It is convenient to let a variable (x) represent that amount. This is said to be 3 times the amount removed from the second pit, so that amount must be x/3.

The amount remaining in the first pit is 90-x.

The amount remaining in the second pit is 75 -x/3.

Since the first pit remaining amount is half the second pit remaining amount, we can write the equation ...

... 90 -x = (1/2)(75 -x/3)

... 180 -2x = 75 -x/3 . . . . multiply by 2

... 105 - 2x = -x/3 . . . . . . subtract 75

... 315 -6x = -x . . . . . . . . multiply by 3

... 315 = 5x . . . . . . . . . . . add 6x

... 63 = x . . . . . . . . . . . . . divide by 5

63 tons of hay were taken from the first pit.

_____

<em>Check</em>

After removing 63 tons from the first pit, there are 27 tons remaining. After removing 63/3 = 21 tons from the second pit, there are 54 tons remaining. 27 is half of 54, so the answer checks OK.

6 0
3 years ago
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