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Elan Coil [88]
3 years ago
11

45 is greater than 21?

Mathematics
2 answers:
Alex17521 [72]3 years ago
5 0

Answer:

45>21

yes it is

<em>Hope</em><em> this</em><em> helps</em>

miv72 [106K]3 years ago
4 0

Answer:

Yes 45 is greater than 21 by 24 numbers

Step-by-step explanation:

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What is 2x2 + 375.65
SpyIntel [72]

Answer:

379.65

Step-by-step explanation:

Multiply first (2 times 2)=4

Then add 4 to 375.65

Hope this helped

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6 0
4 years ago
In the right triangle abc ,
Alenkinab [10]

The midpoint of 'C' is equal to all of the three vertices, since the center of the right triangle is the midpoint then that means the segments, which is 'CC', 'AC', and lastly, 'BC' are mostly congruent.

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I hope this helps, as always. I wish you the best of luck and have a nice day, friend..

6 0
4 years ago
Which expression is equal to 3x? (1 point)
nydimaria [60]

Answer:

the answer is B, because x+x+x is equal to 3×x which is 3x

3 0
3 years ago
Read 2 more answers
Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.
zubka84 [21]

Explanation:

a. It is so easy to double a number that no approximation is necessary.

  31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

__

b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

  6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

  = 32.2×10⁹ = 3.22×10¹⁰ approximately

Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

__

c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.02)×10⁶ ≈ 8.98×10⁶ approximately

The actual value uses all of the digits of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.023)×10⁶ = 8.977×10⁶ exactly

As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

_____

The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

7 0
3 years ago
Q4<br> Help pleaseeeeeeee
emmasim [6.3K]

a. The general equation for a circle centered at (a,b) with radius r is

(x-a)^2+(y-b)^2=r^2

The described circle has equation

(x+3)^2+(y+2)^2=r^2

We know the circle passes through the origin. This means that the equation above holds for x=0 and y=0. The distance between any point on the circle and its center is the radius, so we can use this fact to determine r:

(0+3)^2+(0+2)^2=r^2\implies 9+4=13=r^2\implies r=\sqrt{13}

So the circle's equation is

(x+3)^2+(y+2)^2=(\sqrt{13})^2=13

b. If the distance between point B and the center is less than \sqrt{13}, then B lies inside the circle. If the distance is greater than \sqrt{13}, it falls outside the circle. Otherwise, if the distance is exactly \sqrt{13}, then B lies on the circle.

The distance from B to the center is

\sqrt{(-1+3)^2+(3+2)^2}=\sqrt{4+25}=\sqrt{29}

29>13, so \sqrt{29}>\sqrt{13}, which means B falls outside the circle.

5 0
3 years ago
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