<span>going downstream -
t = 14/(2 + v)
going upstream -
t = 7/(2 - v)
14/(2 + v) = 7/(2 - v)
(2 + v)/2 = 2 - v
v = 2/3km/h</span><span>
</span>
Answer:
See below.
Step-by-step explanation:
Part A:
triangle QPR and triangle PSR are similar
Part B:
Triangle QPR is a right triangle with right angle QPR.
Triangle SPR is a right triangle with right angle PSR.
Angle QPR of triangle QPR corresponds to and is congruent to angle PSR of triangle PSR.
Angle R of triangle QSR corresponds to and is congruent to angle R of triangle PSR.
The similar triangles by AA Similarity are
triangle QPR and triangle PSR
Part C:
QR/PR = PR/SR
16/PR = PR/4
PR² = 16 * 4
PR² = 64
PR = 8
Let the width be x
Length= x+7
Area=lw
99=(x+7)(x)
99=x²+7x
0=x²+7x-99
x= -14.04 or x=7.04
Since a length cannot be negative, the width is 7.04 ft and the length (7.04+7)=14.07 ft
Hope I helped :)
Answer:
29
Step-by-step explanation:
There is a triangle embedded in triangle MNO, which is triangle PQO, and these are similar triangles in that their corresponding sides are always in the same ratio, which in this case is 2:1, as MP = MO due to the midpoint definition, and therefore MO is twice as long as MP. Same for NO and QO.
Now that we know the ratio, we can set 6x-4 = 2(-5x+64)
6x-4 = -10x +108
16x = 112
x = 7
Plug x back in for PQ, -5(7)+64 = 29
Answer:
V≈75.4
Step-by-step explanation:
V=πr^2h/3
v=3.14(3)^2(8)/3=75.4
