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Brrunno [24]
2 years ago
14

Solve y=x+5 and 2x-3y=4

Mathematics
2 answers:
Lyrx [107]2 years ago
8 0

\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }

  • To solve such problem there are two method by elimination method or substitution method
  • I have solved with substitution method juz' refer to attachment for understanding the ans !

{ \boxed{ \: ✟\underline{  \boxed{ \sf{ \: x =  - 19 ✓}}}✟ \:}} \\ { \boxed{ \: ✟\underline{  \boxed{ \sf{ \: y =  - 14✓ }}}✟ \:}} \\\\

Hope it helps !

stepan [7]2 years ago
4 0

Answer:

x= -19

y= -14

Step-by-step explanation:

Substitution.

It tells you what y is already. You substitute that into the second equation and then solve. Then you use that answer and substitute it back into the first equation's x, and then you'll get your full answer.

Hope this helps <3

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Simplify<br> CLEAR Step By Step Explanation Please. <br> Will Mark Brainliest
siniylev [52]

Answer:

1/x+5

Step-by-step explanation:

1. Rewrite 3x as a difference

x-2/x^2 + 5x-2 - 10

2. Factor out x from the equation, then factor out -2.

x-2/ x+(x+5) - 2(x+5)

3. Factor out x+5 from the expression

x-2/ (x+5)(x-2)

4. Reduce the fraction with x-2

x-2 / (x+5) x-2

1/x+5

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

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17.4, since there are no other decimal number values.
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The answer to this question is 0.

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