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3 years ago

List four ratios that are equivalent to 10:4

Mathematics

2 answers:

mestny [16]3 years ago

5 0

80:32, 5:2, 20:8, 50:20

NNADVOKAT [17]3 years ago

3 0

5:2 20:8 30:12 60:16

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The passing yards for the top 5 quarterbacks in the country are 3,832, 3,779, 3,655, 3,642, and 3,579. Find the variance and sta

Leviafan [203]

First get the average passing yards:

(3,832 + 3,779 + 3,655 + 3,642 + 3,579) / 5 = 3,697.4

Now get the squared residuals for each quarterback's passing yards. That is, compute the difference between each data and the average, then square the result. For example,

(3,832 - 3,697.4)^2 = 134.6^2 = 18,117.2

For the others, you should get squared residuals of

6,658.56

1,797.76

3,069.16

14,018.6

Take the sum of the squared residuals, then - since this is a sample, and not a population of all quarterbacks - divide the sum by 5 - 1 = 4 to get the variance:

(18,117.2 + 6,658.56 + 1,797.76 + 3,069.16 + 14,018.6)/4 = 10,915.3

The standard deviation is just the square root of the variance:

√(10,915.3) ≈ 104.48

5 0

3 years ago

Read 2 more answers

Find the sum of all the prime numbers between 20 and 40.

Helga [31]

Answer:

120

Step-by-step explanation:

yw dude

3 0

3 years ago

Solve the equation 3 . 10^4 = 3,600

quester [9]

The solution is false!
3.1 would become a fraction that will be calculated back into a decimal by the 4th power making it 92.3521=3,600.. so the equality is false because the left hand and the right hand side are different.

8 0

2 years ago

Round 0.3782;hundredths

natali 33 [55]

Answer:

hundredth:0.3800

thousand:0.4000

tenth:0.3780

5 0

3 years ago

Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0

3 years ago