$\cfrac{(2g^5)^3}{(4h^2)^3} = \cfrac{2^3 \cdot g^{5\cdot3}}{4^3 \cdot h^{2\cdot3}} = \cfrac{8 g^{15}}{64 h^{6}} =\cfrac{g^{15}}{8h^{6}}$

First option

7 0

2 years ago

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Simplify (-6.5)(2)(-5)

VLD [36.1K]

The answer is 65, hope this helps!

5 0

2 years ago

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Can someone answer #9

In-s [12.5K]

Solution:

First i'm going to divide the graph into 3 parts. Linear, Quadratic and Horizontal graph.

Linear:

$Slope=\frac{-2-0}{-4-(-2)}=1\\y=m(x-xo)+yo\\y=1x-(-2)+(-4)\\y=x-2 , x\leq-1$

Quadratic:

$f(x) = a(x-h)^{2} + k\\f(x)=(x-2)^{2}-7,-1\leq x\geq 6$

Horizontal:

$f(x)=7,x\geq 6$

Answer:

$f(x)=x-2 , x\leq-1\\f(x)=(x-2)^{2}-7,-1\leq x\geq 6\\f(x)=7,x\geq 6$

Hope this was helpful.

8 0

3 years ago