Answer:
12
Step-by-step explanation:
sezxdrcf123456u7tyi7ouy09jiostxdfcghv tghvbyughjgbyugb7nyughb7nyujgkhnuyhkgjhbynuhjgkbynuhijgbyunhjgbyunhgbyuhjg
Answer:
O y = (x + 5) (x + 3)
Step-by-step explanation:
y = (x + 4)² - 1
y = x² + 8x + 15
y = x² + 3x + 5x + 15
y = x(x + 3) + 5(x + 3)
y = (x + 5) (x + 3)
The statement that explains how the company can determine whether pool LMNO is similar to pool PQRS is;
B. Translate PQRS so that point Q of PQRS lies on point M of LMNO, then dilate PQRS by the ratio segment PQ over segment LM.
<h3>How to carry out Transformations?</h3>
Given that quadrilaterals ABCD and EFGH are similar:
The corresponding points on the quadrilaterals are:
P → L
Q → M
R → N
S → O
So, the first step is any of the following:
Translate point P to L
Translate point Q to M
Translate point R to N
Translate point S to O
Notice that the side lengths of PQRS are bigger than that of LMNO
This means that the Quadrilateral PQRS has to be dilated (compressed) by a ratio of side lengths of LMNO divided by side lengths of PQRS
For example, the point M is translated to point Q. The figure will then be dilated by a ratio of LM divided by PQ.
Read more about Transformations at; brainly.com/question/4289712
#SPJ1
[ Answer ]
Y = -12 / 5
[ Explanation ]
Expand:
-3y - 9 = 2y + 3
Add 9 to both sides:
-3y - 9 + 9 = 2y + 3 - 9
Simplify:
-3y = 2y + 12
Subtract 2y from both sides:
-3y - 2y = 2y + 12 - 2y
Simplify:
-5y = 12
Divide both sides by -5:
-5y / -5 = 12 / -5
Simplify:
Y = -12 / 5
<> Arsenal <>
Answer:
(a) 2 degree celsius per hour
(b) 3 degree celsius per hour.
Step-by-step explanation:
From the question,
(a) Avearge rate of rise in temperature per hour(T') = Rise in temperature(T)/Time required for the rise(t).
T' = T/t.................... Euqation 1
Rise in temperature (T) = 4 degree celsius, t = 10.00 am to noon = 2 hours.
Substitute into equation 1
T' = 4/2
T' = 2 degree celsius per hour.
(b) Also,
Average rate of fall in temperature per hour (T') = Fall in temperature (T)/Time(t)
T' = T/t
Given: T = 6 degree celsius, t = 3:00 pm to 5:00 pm = 2 hours
T' = 6/2
T' = 3 degree celsius per hour
