<span>6x+9y = 10500
x+y = 1480
Using elimination I get:
6x + 9y = 10500
-6x-6y = -8880
Add the 2 equations and I get 3y = 1620
Divide both sides by 3 and I get y = 540
Substitute that back in to 6x+9y = 10500.
I get that 6x+9*540 = 10500
9 * 540 = 4860
Subtract 4860 from both sides and I get 6x = 5640
Divide both sides by 6 and I get x = 940
So there must have be 940 children and 540 adults</span>
Change the fractions into decimals first.
If the decimal is for example 1.56565656... and so on, it is repeating. Because as you can see, the number 56 is repeating. If the decimal is for example 1.456 and there is no number afterwards, means that it is terminating.
Look at the number in the thousands place. This number is 6. Now look at the number after it. It is 4. 4 is less than 5 so you keep 6 the same. Now you make the rest 0s, except for the 1 before the 6. The estimate would be 16,000.
Answer: the constant term is 14.
Step-by-step explanation:
We have that
<span>the point (7, 1)
case </span><span>A.) y = 5x + 4
if the point </span>(7, 1) lie to the line
so
for x=7 the value of y must be 1
y=5*7+4------> y=39
39 is not 1---------> the point does not belong to the line
case <span>B.) y = -x + 8
</span>if the point (7, 1) lie to the line
so
for x=7 the value of y must be 1
y=-7+8------> y=1--------> the point belongs to the line
case <span>C.) y = x - 10
</span>if the point (7, 1) lie to the line
so
for x=7 the value of y must be 1
y=7-10------> y=-3
-3 is not 1---------> the point does not belong to the line
case <span>D.) y = -4x + 3
</span>if the point (7, 1) lie to the line
so
for x=7 the value of y must be 1
y=-4*7+3------> y=-25
-25 is not 1---------> the point does not belong to the line
the answer is the option
B.) y = -x + 8
