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kvasek [131]
3 years ago
5

Shane is using pieces of square paper to cover a cube shaped gift with sides that are 9 inches long to find out the area of the

paper he needs,he uses the formula for surface area of a cube A=6s to the power of 2.What is the surface area of the cube.
Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

486 Square inches

Step-by-step explanation:

Side Length of the Cube = 9 Inches

For a cube of side length s, Surface Area, A=6s^2

In this case, s=9 Inches

Therefore:

Surface area of the cube

A=6*9^2\\=486$ Square inches

The surface area of the cube is 486 Square inches. Therefore Shane will need 486 Square inches of paper.

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horsena [70]


12.56=fraction?

here Is the 2 fractions

12 56 /100

or

"simplified "

12 14/25

hoped this helped :)


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How many cups are in 3 gallons? 1 gallon = 16 cups<br><br> Label your answer in cups.
shepuryov [24]

Answer:

48 cups

Step-by-step explanation:

16 times 3

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Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)
USPshnik [31]

\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k

\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k

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Then the length of the arc is

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3 years ago
Using f(x) = 4x + 6 with a domain of {-1, 0, 2 }, find the range.
lianna [129]

Answer:

{2, 6, 14}

Step-by-step explanation:

Using f(x) = 4x + 6 with a domain of {-1, 0, 2 }, find the range.

To get the range, we will substitute the values of the domain into the given function as shown;

when x = -1

f(-1) = 4(-1)+6

f(-1) = -4+6

f(-1) = 2

when x = 0

f(0) = 4(0)+6

f(0) = 0+6

f(0) = 6

when x = 2

f(2) = 4(2)+6

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6 0
3 years ago
What is the value of a1 of the geometric series? Sigma-Summation Underscript n = 1 Overscript infinity EndScripts 12 (negative o
worty [1.4K]

Answer:

12

Step-by-step explanation:

The given geometric series is

\sum_{n = 1}^{ \infty} 12( { -  \frac{1}{9} })^{n - 1}

We want to determine the first term of this geometric series.

Recall that the explicit formula is

a_{n} = 12( { -  \frac{1}{9} })^{n - 1}

To find the first term, we put n=1 to get:

a_{1} = 12( { -  \frac{1}{9} })^{1 - 1}

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