Answer:
Part A = 10in = 35 ft
= 20 = 70 ft
Part B =
$ 178.5
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
The sorted data set is ...
1 2 3 3 5 7 8 9
The median is the average of the middle two numbers: (3+5)/2 = 4.
Replacing one of the 3s with a 1 makes the data set be ...
1 1 2 3 5 7 8 9
The average of the middle two numbers is (3+5)/2 = 4.
The median increases by 4 - 4 = 0.
Answer:
125 deg
Step-by-step explanation:
Keep these three rules in mind:
1) A central angle (vertex is the center of the circle) has the same measure as the arc it intercepts.
2) The measure of an inscribed angle (vertex is point on circle) is half the measure of the intercepted arc.
3) Opposite angles of a rectangle inscribed in a circle are supplementary.
110 deg is a central angle.
By rule 1), the arc intercepted by the central angle 110 deg also measures 110 deg.
a is an inscribed angle that intercepts an arc of 110 deg.
By rule 2), the measure of an inscribed angle is half the measure of the intercepted arc.
angle a measures 55 deg.
Rule 3) Angles a and b are supplementary.
a + b = 180
55 + b = 180
b = 125
34 is the original number.
This is because 34 times 2 is 68 and 68 plus 3 is 71.
Answer:
0.91517
Step-by-step explanation:
Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.
Let A - the event passing in SAT with atleast 1500
B - getting award i.e getting atleast 1350
Required probability = P(B/A)
= P(X>1500)/P(X>1350)
X is N (1100, 200)
Corresponding Z score = 
