Uma mulher com prou 171 capacetes e 1/9 veio com defeitos quantos capacetes estavam perfeitos para uso

Mathematics

1 answer:

garri49 [273]3 years ago

3 0

Responder:

152 capacetes

Explicação passo a passo:

Dado que:

Número de capacetes = 171

Fração com defeito = 1/9

Portanto, número de capacetes com defeito:

1/9 * 171 = 19 capacetes

Número de capacetes sem defeitos:

Número total de capacetes - número de capacetes defeituosos

171 - 19 = 152 capacetes

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The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

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Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$