![\frac{4}{9} x = \frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B9%7D%20x%20%3D%20%20%5Cfrac%7B1%7D%7B6%7D%20)
Divide each side by 4/9 // Multiply the reciprocal, which would be 9/4
![\frac{9}{4} \times ( \frac{4}{9} x) = \frac{9}{4} \times \frac{1}{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%7D%7B4%7D%20%20%5Ctimes%20%28%20%5Cfrac%7B4%7D%7B9%7D%20x%29%20%3D%20%20%5Cfrac%7B9%7D%7B4%7D%20%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B6%7D%20)
Which would leave you with
Here it is given that f(x)=3x and g(x)=1/x
We have to find the domain of (g o f)(x)
Now it is given that f(x) = 3x
and it is also given that g(x) = 1/x
so (g o f)(x) = g( f(x) ) = g( 3x )
which comes out to be 1 / 3x
The domain of the expression is all the real numbers except where the expression is undefined so the domain of the given expression is all real numbers except 0.
Answer:
30 red marbles
Step-by-step explanation:
If the ratio is 2 red marbles for every 5 blue marbles then you would add them together to find out how many marbles are in one group.
2+5=7
There are 7 marbles in each group.
Now we have to find out how many total groups there are by dividing the total amount of marbles by the amount in each group.
105÷7=15
There are 15 groups of 7 marbles.
Looking back at the ratio, we know that the 15 groups each have 2 red marbles and 5 blue marbles. So if there is 2 red marbles 15 times (2 marbles in 15 groups) we would multiply.
2×15=30
There are 30 red marbles.
I hope that makes sense.
First, solve for either x or y. Since the first is already solved for x, solve the second for x as well;