Question

if the ratio of the ages of kisii and esinam is 3:5 and that of Esinam and Larry is 3:5 and the sum of the ages of all three is 147 years what is the age difference between the oldest and the youngest​

Answer 1

Answer:

The age difference between the oldest and the youngest is 48.

Explanation:

Given the following data;

The ratio of the ages of Kisii (K) and Esinam (E) is 3:5.

The ratio of the ages of Esinam (E) and Larry (L) is 3:5.

The sum of the ages of all three is 147.

Since the age of Esinam is common in both ratios, we find the lowest common multiple (LCM);

LCM of 3,5 = 15.

Hence, the ratio of the three ages is now;

K:E:L = 9:15:25

Let their ages be denoted by x;

$K:E:L = 9x:15x:25x$

The sum of all three ages is;

9x + 15x + 25x = 147

49x = 147

x = 147/49

x = 3.

To find the age difference between the oldest and the youngest;

The oldest is Esinam = 25x

The youngest is Kisii = 9x

Therefore, 25x - 9x = 16x

Substituting the value of x, we have;

x = 3; 16x = 16(3) = 48.

The age difference between the oldest and the youngest is 48.