Answer:
The number of units earned by Calendula College students during the spring term.
Step-by-step explanation: hope this helps :)
The <span>piece of fabric is </span>26.24cm squared
Answer:
706.5 ft²
Step-by-step explanation:
A. Width of the rectangle
The formula for the area of a rectangle is
A = lw
But, l = 3w, so,
A = (3w)w
= 3w² = 12
w² = 4 Divided each side by 3
w = 2 ft Took the square root of each side
B. Length of rectangle
l = 3w = 6 ft
C. Diameter of circle
d = 5l = 5 × 6 = 30 ft
D. Radius of circle
d = 2r
r = d/2 Divided each side by 2
r = 30/2 = 15 ft
E. Area of circle
A = πr² = 3.14 × 15² = 3.14 × 225 = 706.5 ft²
The area of the circle is 706.5 ft².
Let the coordinates of the circumcentre O of the triangle DEF be (x, y). Circumcentre of a triangle is equidistant from each of the vertices.
1. Distance OD=distance OE, then:
.
2. Distance OD=distance OE, then:
.
Solve the system:
,
,
.
Then
.
Answer: the coordinates of the circumcenter for ∆DEF are x=4.5, y=-1.
About 405 hours
i got the answer by multiplying
hope this helped you!
