A solution with a pH of 11 has a [H+] of 
Option B is correct option.
Step-by-step explanation:
A solution with a pH of 11 has a [H+] of= ?
pH=?
Concentration of H+ [H+]= ?
Formula used: ![pH=-log[H+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%2B%5D)
Putting values and finding [H+]
![pH=-log[H+]\\\,[H+]\,=10^{-pH}\\\,[H+]\,=10^{-11}\\\,[H+]\,=1.0\times 10^{-11}](https://tex.z-dn.net/?f=pH%3D-log%5BH%2B%5D%5C%5C%5C%2C%5BH%2B%5D%5C%2C%3D10%5E%7B-pH%7D%5C%5C%5C%2C%5BH%2B%5D%5C%2C%3D10%5E%7B-11%7D%5C%5C%5C%2C%5BH%2B%5D%5C%2C%3D1.0%5Ctimes%2010%5E%7B-11%7D)
So, A solution with a pH of 11 has a [H+] of
Option B is correct option.
Answer:
x = 2
Step-by-step explanation:
You are solving for the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS is the order of operation, and =
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction.
First, subtract 25 from both sides of the equation:
5x + 25 (-25) = 35 (-25)
5x = 35 - 25
5x = 10
Isolate the variable, x. Divide 5 from both sides:
(5x)/5 = (10)/5
x = 10/5
x = 2
x = 2 is your answer.
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There are no real solutions to that equation.
