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seraphim [82]
3 years ago
13

2³+b²+3²=?hihihihihihihi

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer:

b^2+17

Step-by-step explanation:

2^3 is 8 (2*2*2=8)

b^2 stays the same bcz its a variable and we don't know its value

3^2 is 9 (3*3=9)

SO just substitute,

8+b^2+9

b^2+17

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I just need help with this
Alexxx [7]

Answer:

z = 4.5

Step-by-step explanation:

∠B = ∠B      ∠BAD = 90° - ∠B = ∠C

ΔBAD ~ ΔBCA

AB / z = BD / AB

z = AB * AB / BD = 3*3 / 2 = 4.5

3 0
3 years ago
In a survey of 3,000 people who owned a certain type of​ car, 1,050 said they would buy that type of car again. What percent of
Ray Of Light [21]

Answer:

35 percent

Step-by-step explanation:

1050 / 3000 as a percent

1050 / 3000 = 105 / 300

Divide both sides by 3:

300 / 3 = 100

105 / 3 = 35

35 / 100 = 35 percent

3 0
2 years ago
Read 2 more answers
Solve for x<br><br> explain how to do it pls
Arte-miy333 [17]
X=7

(15x+3)=108
x=7

if you plug 7 in for x

(15(7)+3) it equals 108
7 0
3 years ago
The derivative of y with respect to x, when y = 3e^5x - 2 is:
Ede4ka [16]
Answer: 15e^5x

Step - by - step

y=3e^5x - 2

By the sum rule, the derivative of 3e^5x - 2 with respect to x is d/dx [ 3e^5x ] + d/dx [-2].

d/dx [ 3e^5x ] + d/dx [ -2 ]

Evalute d/dx [ 3e^5x ]

Since 3 is constant with respect to x , the derivative of 3e^5x with respect to x is
3 d/dx [ e^5x ].

3 d/dx [ e^5x ] + d/dx [ -2 ]

Differentiate using the chain rule, which states that d/dx [ f(g(x))] is f' (g(x)) g' (x) where f(x) = e^x and g(x) = 5x.

To apply the Chain Rule, set u as 5x.
3 ( d/du [ e^u] d/dx [5x] ) + d/dx [ -2]

Differentiate using the Exponential rule which states that d/du [ a^u ] is a^u ln(a) where a=e.

3( e^u d/dx[5x] ) + d/dx [ -2 ]
Replace
3(e^5x d/dx [5x] ) + d/dx [ -2 ]
3(e^5x( 5 d/dx [x] )) + d/dx [ -2 ]

Diffentiate using the Power Rule which states that d/dx [x^n] is nx^n-1 where n=1.
3(e^5x(5*1)) + d/dx [-2]
3 ( e^5x * 5 ) + d/dx [-2]

Multiply 5 by 3
15e^5x + d/dx [-2]

Since -2 is constant with respect to x, the derivative of -2 with respect to x is 0.
15e^5x + 0
15e^5x
5 0
1 year ago
A football is kicked into the air. The height of the football can be modeled by the equation
Alinara [238K]

Answer:

x = 0 and x = 1

Step-by-step explanation:

Given that,

A football is kicked into the air. The height of the football can be modeled by the equation :

h = -16x^2 + 16x

Where

h is the height reached by the ball after x seconds

When it touches the ground, h = 0

So,

-16x^2 + 16x=0\\\\16x(-x+1)=0\\\\x=0\ and\ x=1

So, it will touch the ground at x = 0 and x = 1 seconds.

6 0
3 years ago
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