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Flura [38]
3 years ago
7

How many grams of NaCl can be produced from 4.2 moles of Cl2?

Chemistry
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

491.4 g

Explanation:

This a stoichiometry question, let me repeat the reaction equation here;

2 Na + Cl2 --> 2 NaCl

The balanced reaction equation must serve as a guide in solving any problem on stoichiometry.

From the balanced reaction equation;

1 mole of chlorine gas yields 2 moles of sodium chloride

Therefore, 4.2 moles of chlorine gas yields 4.2 ×2/1 = 8.4 moles of sodium chloride.

Molar mass of sodium chloride= 23 + 35.5= 58.5 gmol-1

Mass of sodium chloride formed= number of moles × molar mass

Mass of sodium chloride formed= 8.4 × 58.5= 491.4 g

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What are the two functional group present in the molecule
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carboxyl group (COOH) and amines

Explanation:

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What is the periodic # for uranium?
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4 0
4 years ago
Read 2 more answers
Would you expect the carbonyl carbon of benzaldehyde to be more or less electrophilic than that of acetaldehyde? Explain using r
Slav-nsk [51]

Answer:

Benzaldehyde is less electrophilic than acetaldehyde

Explanation:

Electrophilicity of carbonyl carbon depends on it's positive charge density.

In benzaldehyde, phenyl group can act as an electron donating group towards carbonyl group due to it's electron donating resonating effect.

In acetaldehyde, methyl group can act as an electron donating group towards carbonyl group due to it's electron donating inductive effect.

We know that resonating effect are more stronger than inductive effect.

Henece, it is expected that positive charge density on carbonyl carbon is much lower in benzaldehyde than acetaldehyde.

So, benzaldehyde is less electrophilic than acetaldehyde.

Resonating effect of phenyl group has been shown below.

4 0
3 years ago
If you dilute 18.8 mL of a 3.5 M solution to make 296.6 mL of solution, what is the molarity of the dilute solution?
hodyreva [135]

Answer:

0.22M

Explanation:

We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.

So: moles before dilution = moles after dilution & moles_{concentrated} = moles_{dilute}. And M = moles/liter of solution, so if we express this as moles = M x L_{soln}.

That is how we derive the formula we will be using: M_{concentrated} * Vol_{conc} = M_{dilute} * Vol_{dilute}

or

M_{1} * Vol_{1} = M_{2} * Vol_{2}

Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.

M1 = 3.5M

V1 = 18.8mL

M2 = ?

V2 = 296.6mL

Equation: (3.5M)(18.8mL) = (296.6mL)(M2)

==> 65.8M*mL = 296.6mL * M2

==> M2 = (65.8 M*mL)/296.6mL

==> M2 = 0.22M

8 0
3 years ago
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