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tester [92]
3 years ago
7

There are many factors that influence the population changes of an ecosystem. Which of these does not influence population size

in an ecosystem? A. Birthrates of animals B. An animal's weight C.Number of animals in habitats D.Number of animals in habitats
Chemistry
2 answers:
devlian [24]3 years ago
7 0

Answer:

B. An animal's weight

Explanation:

An animal's weight is the factor that does not influence population size in an ecosystem because this factor does not cause an increase or decrease the population of animals in an ecosystem. The birth and death rate of animals and number of animals in habitats are the factors that tells us about the increase and decrease in the population of organisms in an ecosystem but weight of organism can't affect the population.

nirvana33 [79]3 years ago
5 0

Answer:

B. An animal's weight

Explanation:

Population growth is based on four fundamental factors: birth rate, death rate, immigration, and emigration.

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Empirical Formula of P3O4H2?
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3 years ago
CsH«N2(l) + CuCl(s)
bulgar [2K]

0.498 moles of copper(II) phthalocyanine would be produced by

the complete cyclotetramerization of 255 grams of phthalonitrile in the

presence of excess copper(ll) chloride.

<em>Copper(ll) phthalocyanine (Cu(C₃₂H₁₆N₈)) is produced by the cyclotetramerization of phthalonitrile (C₈H₄N₂) according to the following reaction: 4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g) How many moles of copper(II) phthalocyanine would be produced by the complete cyclotetramerization of 255 grams of phthalonitrile in the presence of excess copper(II) chloride?</em>

Let's consider the following balanced equation.

4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g)

The molar mass of C₈H₄N₂ is 128.13 g/mol. The moles corresponding to 255 g of C₈H₄N₂ are:

255 g \times \frac{1mol}{128.13 g} = 1.99 mol

The molar ratio of C₈H₄N₂ to Cu(C₃₂H₁₆N₈) is 4:1. The moles of Cu(C₃₂H₁₆N₈) produced from 1.99 moles of C₈H₄N₂ are:

1.99 mol C_8H_4N_2 \times \frac{1molCu(C_{32}H_{16}N_8)}{4mol C_8H_4N_2} = 0.498 mol Cu(C_{32}H_{16}N_8)

0.498 moles of copper(II) phthalocyanine would be produced by

the complete cyclotetramerization of 255 grams of phthalonitrile in the

presence of excess copper(ll) chloride.

You can learn more about stoichiometry here: brainly.com/question/22288091

8 0
2 years ago
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