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Finger [1]
3 years ago
9

What is the periodic # for uranium?

Chemistry
2 answers:
gregori [183]3 years ago
8 0

Answer:

it is 92

Explanation:

ruslelena [56]3 years ago
4 0

Answer:

92

Explanation:

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Grease and non-polar too, so the <span>tetrachloroethylene would be a solvent.</span>
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4 0
3 years ago
Naproxen sodium, also known as Sodium 6-methoxy-α-methyl-2-napthaleneacetate, (C14H13NaO3), is an anti-inflammatory medication,
swat32

1) molar mass of C₁₄H₁₃NaO₃ = 252 g/mole

2)  number of moles of naproxen sodium = 0.00119 moles

3) 0.00238 moles of naproxen in one day

Explanation:

1) Determine the molar mass of naproxen sodium.

We know that the molecular formula of naproxen sodium is C₁₄H₁₃NaO₃.

Now we can calculate the molar mass of naproxen sodium:

molar mass of C₁₄H₁₃NaO₃ = molar mass of C × 14 + molar mass of H × 13 + molar mass of Na × 1 + molar mass of O × 3

molar mass of C₁₄H₁₃NaO₃ = 12 × 14 + 1 × 13 + 23 × 1 + 16 × 3

molar mass of C₁₄H₁₃NaO₃ = 252 g/mole

2) Calculate the number of moles of naproxen sodium in a single tablet.

Knowing that one tablet contains 300 mg = 0.3 g of naproxen sodium, we use the following formula to find the number of moles:

number of moles = mass / molar weight

number of moles of naproxen sodium = 0.3 / 252

number of moles of naproxen sodium = 0.00119 moles

3) Calculate the number of moles of naproxen sodium that an adult would have taken if she took two doses of naproxen sodium in one day.

To find the number of moles taken by the adult in one day we follow the next reasoning:

if       1 tablet of naproxen contains 0.00119 moles of naproxen

then 2 tablets of naproxen contains X moles of naproxen

X = (2 × 0.00119) / 1 = 0.00238 moles of naproxen

Learn more about:

number of moles

brainly.com/question/14115874

brainly.com/question/14124542

#learnwithBrainly

8 0
3 years ago
PLEASE HURRY!!
AysviL [449]

Answer:

Molar mass of acetic acid is 60 g/mol

Explanation:

Look at the formula:

CH₃COOH

We have:

  • 2 moles of C → 12.011 amu . 2 = 24 g/mol
  • 4 moles of H →  1.008 amu . 4 = 4 g/mol
  • 2 moles of O → 15.999 amu . 2 = 32 g/mol

Let's sum the mass of each element

24 g/mol + 4 g/mol + 32 g/mol = 60 g/mol

8 0
3 years ago
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