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earnstyle [38]
3 years ago
7

Simplify. Assume that no denominator is equal to zero.

Mathematics
2 answers:
Rus_ich [418]3 years ago
5 0
You gots to explain that Better man
alexandr1967 [171]3 years ago
3 0

The answer is B  a^9 8b^4

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Mrs. Henderson has 16 boys in her class of 24 students. Mr. Gregory has 18 boys in his class of 30 students. which class has the
oksano4ka [1.4K]
Me. Gregory's class has the greatest ratio of boys to students.
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4 years ago
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Look at the equation below. Identify which equation has no solution
IgorC [24]

Answer:

C

Step-by-step explanation:

24a-22  = -4(1-6a)\\\\\implies 24a-22  = -4+24a\\\\\implies -22 = -4\\\\\text{Which is not true, so no solutions exist.}

4 0
2 years ago
A boy throws a baseball across a field. The ball reaches its maximum height, 18 meters, after 1 second. After approximately 2.3
Jobisdone [24]
That would be 
 -10(1.5)^2 + 20(1.5) + 8  =   15.5 meters
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3 years ago
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Wayne's class is building a wagon to be used as a float for the upcoming Pioneers Day Parade. The outsides of the four wagon whe
dalvyx [7]

Answer:

30

120

706.5

Step-by-step explanation:

circumference= 94.2 inches, circumference is pi x diameter so-

diameter = 94.2/pi inches.

Using 3.14 as an approximation for pi we get:

Diameter=30 inches.

So would need a length of at least

4x30 = 120 inches of felt for four wheels.

The area of the circular wheel is pi x diameter 2/4 square inches.

Area is 706.5 square inches which is how much felt is needed to cover one wheel.

3 0
3 years ago
Help!!!!!!!!!!!!!!!!
Andru [333]

Step-by-step explanation:

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9

let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9

let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9

You can continue to increase the length of the square and follow this pattern and it will be consistent.

7 0
3 years ago
Read 2 more answers
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