I would say this animal lives in a snowy environment.
Have a good day! =)
Answer: 20 fragments
Explanation:
This particular restriction enzyme has a 4 bp (base pair) recognition sequence therefore it will cleave once every 4ⁿ bases where n indicates the number pf bases in the recognition sequence.
- The recognition sequence is 4 bp therefore this restriction enzyme cleaves once every 4⁴ = 256 bases. This is the length of the restriction fragment.
- Calculate the number of fragments by dividing the total number of bases ( where you assume equal frequency of bases ie. A+T = C+G) by the length of the restriction base.
- therefore 5000bp/256bp = <u>19,53</u> now this number ca n be rounded up to 20.
- The expected number of fragments on the electrophoresis gel will be 20 fragments.
Answer:
C. I and III
Explanation:
A mutation needs to occur in a gamete cell in order to be passed down to the next generation.
If it occurs in a somatic (body) cell, the mutation will only be present in that organism.
On the other hand, in a gamete cell, the mutation will pass down because gamete cells are directly involved in the genetic makeup of the offspring.
So, since sperm and egg cells are gametes, mutations in those cells would get passed on.
The correct answer is C. I and III
