Question

What is the missing constant term in the perfect square that starts with x2+18xx^2+18xx2+18xx, squared, plus, 18, x ?

Answer 1

Answer:

81

Step-by-step explanation:

Given the expression: $x^2+18x$

To make it a perfect square, we follow the following steps.

Divide the coefficient of x by 2

• Coefficient of x=18, 18/2=9

Square It

• 9 X 9=81

Add it to the expression

• $x^2+18x+81$

This is written as a perfect square as: $(x+9)^2$

The constant term required therefore is 81.

Answer 2

Answer:

This is written as a perfect square as $(x+9)^2$

The constant term required therefore is 81.

Step-by-step explanation:

Given that;

The expression $x^2+18x$

we follow the following steps.

Divide the coefficient of x by 2

Coefficient of

$x = 18, \\\\18 \div2=9$

Square 9

9² = 81

The expression goes

$x^2+18x+81$

This is written as a perfect square as $(x+9)^2$

The constant term required therefore is 81.