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luda_lava [24]
3 years ago
5

What is the missing constant term in the perfect square that starts with x2+18xx^2+18xx2+18xx, squared, plus, 18, x ?

Mathematics
2 answers:
katrin2010 [14]3 years ago
4 0

Answer:

81

Step-by-step explanation:

Given the expression: x^2+18x

To make it a perfect square, we follow the following steps.

Divide the coefficient of x by 2

  • Coefficient of x=18, 18/2=9

Square It

  • 9 X 9=81

Add it to the expression

  • x^2+18x+81

This is written as a perfect square as: (x+9)^2

The constant term required therefore is 81.

frozen [14]3 years ago
3 0

Answer:

This is written as a perfect square as (x+9)^2

The constant term required therefore is 81.

Step-by-step explanation:

Given that;

The expression x^2+18x

we follow the following steps.

Divide the coefficient of x by 2

Coefficient of

x = 18, \\\\18 \div2=9

Square 9

9² = 81

The expression goes

x^2+18x+81

This is written as a perfect square as (x+9)^2

The constant term required therefore is 81.

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