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ivann1987 [24]
3 years ago
6

A mountain road is 5 miles long at a Constant rate. After 2 miles, the elevation is 5500 feet above sea level. After 4 miles, th

e elevation is 6200 feet above see level. Find the elevation on the road at the point where the road begins
Mathematics
1 answer:
olchik [2.2K]3 years ago
5 0

Answer:

The road is 4800 ft above sea level

Step-by-step explanation:

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Use the number line to add the fraction.
horrorfan [7]

Answer:

1/8

Step-by-step explanation:

-5/8 + 3/4 = -5/8 + 6/8 = 1/8

3 0
2 years ago
Read 2 more answers
39 is 150% of what number plz show work
slava [35]
Okay 39 is 150% of what number? so like remember whenever you see percent you have to divide by 100
so let's start
First. we have 150% so let's divide 150%/100=1.5

Second. you will multiply 1.5*39= 26% 

and you can also do it like easy way.

39/150=0.26
0.26/100=26

39 is 26% of 150

hope i help :p
3 0
3 years ago
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Thom's restaurant bill is 45$ and he leaves a 20 percent tip. what is the total cost for thom's meal
katrin [286]
The total cost of the meal will be $54.
45 + 20% = 54
5 0
3 years ago
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Each class briarwood elementary collect at least 54 of food during the drive. If there are 29 classes in the school,what was the
julia-pushkina [17]

Answer:

1566

Step-by-step explanation:

20*50=1000

20*4=80

<h3>1000+80=1080</h3>

9*50=450

9*4=36

450+81=486

<h2>1080+486=1566</h2>
4 0
3 years ago
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The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and
strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

                                   X ~ N ( u , s /√n )

Where

                            s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

                        P ( 5 < X < 10 ) = P (    (5 - 8) / 0.2143 <  Z  <  (10-8) / 0.2143   )

                                                 = P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

                        P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1        

7 0
3 years ago
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