5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Answer:
7()=11
8()=42
I could barely see the answer for number 9 sorry :(
Step-by-step explanation:
the 7() is 2(3)+5
2(3)=6
6+5=11
Question (8)
c^2+3a x b
c(6)^2+ 3(3) x 2/3
36+9 x 2/3
36+6=42
Answer:
Thats not a full question
Step-by-step explanation:
A) i think is the correct answer
The answer to 2-(-8)+(-3)= 7
