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Oliga [24]
3 years ago
7

Claire Reagan and Anthony deliver newspapers in the neighborhoods clear deliver 79 papers a day Reagan delivers 2490 papers a mo

nth Anthony delivers 616 papers a week how many do they deliver together in a year
Mathematics
2 answers:
Nata [24]3 years ago
4 0

Answer:

90,747

Step-by-step explanation:

Clair delivery=79 per day

Total delivery per year=79×365 days

=28,835

Reagan delivery=2490 per month

Total delivery per year=2490×12 months

=29,880

Anthony delivery= 616 per week

Total delivery per year =616×52 weeks

=32,032

Total delivery altogether in a year=28,835+29,880+32,032

=90,747

Charra [1.4K]3 years ago
4 0

Answer:

Step-by-step explanation:

Clair delivers 79 papers a day.

Assuming that there are 365 days in a year, it means that the number of newspapers that Clair delivers in a year is

79 × 365 = 28835

Reagan delivers 2490 papers a month. There are 12 months in a year. it means that the number of newspapers that Reagan delivers in a year is

12 × 2490 =29880

Anthony delivers 616 papers a week. Assuming that there are 52 weeks in a year, it means that the number of newspapers that Anthony delivers in a year is

52 × 616 = 32032

Therefore, the number of newspapers that they deliver altogether in a year is

28835 + 29880 + 32032 = 90747

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A picture is 46 cm by 32 cm. A scale diagram of the picture must fit in a space that is 3 m by 2 m. Which scale would be the mos
Marrrta [24]

Answer:

A picture that is 46cm by 32 cm must fit in a space that is 3m by 2m

First, let's rewrite both of these dimensions in the same units.

Knowing that:

1m = 100cm

Then the dimensions of the space can be rewritten from:

3m by 2m

to:

300cm by 200cm

So, if we enlarge our original picture by a scale factor K, the new dimensions of the picture will be:

K*46cm by K*32cm

Now we just need to find a value of K such that:

K*46cm is something near to 300cm

K*32cm is something near to 200cm

First, we can solve the equation:

K*46cm = 300cm

solving this for K we get:

K = 300cm/46cm = 6.5

While if we solve the equation:

K*32cm = 200cm

we get:

K = 200cm/32cm = 6.25

So we got two possible scale factors.

Which one we should take?

Notice that if we wanted to use the larger one (K = 6.5) for the 32cm side. the new length would be:

32cm*6.5 = 208cm

This is larger than the 200cm of space that we have

Then we can not select the larger option, we can only take the other value:

K = 6.25

Then we can conclude that a reasonable scale factor to use is K = 6.25

4 0
2 years ago
A scatter plot is shown.<br><br><br> Which statement is true for the scatter plot?
sergey [27]
We need the multi choices to answer that
5 0
2 years ago
Use the given information to find the exact value of the trigonometric function
eimsori [14]
\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}

Half Angle Formula

\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\  \\  \end{gathered}

Answer:

\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}

Checking:

\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{  (3rd quadrant)} \end{gathered}

Also,

\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}

The answer is none of the choices

7 0
1 year ago
Which of the following is the minimum value of the equation y = 2x2 + 5?
raketka [301]
(0, 5) is the minimum value.

Find the axis of symmetry by plugging the respective variables into -b/2a

-5/2(0) = 0

There is no b-value in our equation, or rather, the value of b is 0. To see this, y = 2x^2 + 5 can be written as

y = 2x^2 + 0x + 5

We plug 0 into f(x), establishing every x-value as 0.

f(0) = 2(0)^2 + 5
f(0) = 0 + 5
f(0) = 5

5 is now your vertex’s y-value. Plot the two values together.

(0, 5)

We know that this is a minimum because the leading coefficient is positive, meaning the the graph’s parabola will open down.
4 0
2 years ago
a local little League has a total of 60 players of whom 20%are left handed .how many left handed players are there?​
valentinak56 [21]

Answer:

Step-by-step explanation:

left handed players : 20% of 60

turn ur percent to a decimal...." of " means multiply

0.20 * 60 = 12 are left handed

7 0
3 years ago
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