Answer:
#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.
#4.) Find how many minutes until the barrel is empty of water.
Let y = 0, to solve for time x.
0 = (-2/5)*x + 18
(2/5)*x = 18
x = (5/2)* 18 = 5*9 = 45 minutes
Up to and after 45 minutes, the barrel is empty of water.
Step-by-step explanation:
#2.)
minutes: 5, 10, 15, 20
water(gal): 16, 14, 12, 10
Find slope: slope m = (14 - 16)/(10 - 5) = -2/5
y - 10 = (-2/5)*(x - 20)
y - 10 = (-2/5)* x + 8
y = (-2/5)*x + 18
rate of change slope means that for every minute 2/5 gallons of water is lost
#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.
#4.) Find how many minutes until the barrel is empty of water.
Let y = 0, to solve for time x.
0 = (-2/5)*x + 18
(2/5)*x = 18
x = (5/2)* 18 = 5*9 = 45 minutes
If sqrt x is around 3.4
x=(3.4)(3.4)=11.56
So x is in between 11 and 12 or
11
Hope this can help.
Use the proportion equation. Cross multiply. Answer is 10.4%
You add 25 and 22 and it adds up to 47 so the answer is 47
Answer:
try D it seems right to me
