26,000 + 10(52)(7.5) + 0.10(25,000) =
26,000 + 3900 + 2500 =
32,400 <== total early income
Hi there!
The linear equation would be y = 3x + 11. This is because the slope is 3, found by using the formula (y2-y1 / x2-x1). Then, we can plug in the slope and a point into y=mx+b form. Next, we can plug in 0 for x and 0 for y to figure out if the line goes through the point (0,0). Doing this, we discover that the line does not go through the point (0,0).
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Part A: x = -5/4, 3 || (-5/4, 0) (3, 0)
To find the x-intercepts, we need to know where y is equal to 0. So, we will set the function equal to 0 and solve for x.
4x^2 - 7x - 15 = 0
4 x 15 = 60 || -12 x 5 = 60 || -12 + 5 = -7
4x^2 - 12x + 5x - 15 = 0
4x(x - 3) + 5(x - 3) = 0
(4x + 5)(x - 3) = 0
4x + 5 = 0
x = -5/4
x - 3 = 0
x = 3
Part B: minimum, (7/8, -289/16)
The vertex of the graph will be a minimum. This is because the parabola is positive, meaning that it opens to the top.
To find the coordinates of the parabola, we start with the x-coordinate. The x-coordinate can be found using the equation -b/2a.
b = -7
a = 4
x = -(-7) / 2(4) = 7/8
Now that we know the x-value, we can plug it into the function and solve for the y-value.
y = 4(7/8)^2 - 7(7/8) - 15
y = 4(49/64) - 49/8 - 15
y = 196/64 - 392/64 - 960/64
y = -1156/64 = -289/16 = -18 1/16
Part C:
First, start by graphing the vertex. Then, use the x-intercepts and graph those. At this point we should have three points in a sort of triangle shape. If we did it right, each of the x-values will be an equal distance from the vertex. After we have those points graphed, it is time to draw in the parabola. Knowing that the parabola is positive, we draw in a U shape that passes through each of the three points and opens toward the top of the coordinate grid.
Hope this helps!
Answer:
I think 7
Step-by-step explanation:
4 , 8 , 9 and 12 has factors.
7 has no factor.
4= 2×2
8= 2×4
9= 3×3
12= 3×4
Select all the options because a rectangle can be made of all dimensions.
