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Anuta_ua [19.1K]
3 years ago
5

A map is drawn with a scale of 1 inch equal to 5 actual miles.

Mathematics
1 answer:
SashulF [63]3 years ago
8 0

Answer:

A. 40 Miles

Step-by-step explanation:

To find the answer I'd use a proportion. To do this you would set it up like this: \frac{1 inches}{5 miles} = \frac{8 inches}{x miles}

Then you could either cross multiply or do it the way I'm going to explain. 1 time 8 equals 8, and when you multiply the top number you have to multiply the bottom number by the same number. So 5 time 8 equals 40. The real distance between the cities is 40 miles.

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svlad2 [7]

Answer:

5 hours

Step-by-step explanation:

45 times 5 = 225

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Answer: Hexagon

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Use the Laplace transform to solve differential equation
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Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7) 
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
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4 0
3 years ago
If LaTeX: m\angle ABF=8s-6m ∠ A B F = 8 s − 6 and LaTeX: m\angle ABE=2\left(s+11\right)m ∠ A B E = 2 ( s + 11 ), find LaTeX: m\a
kolbaska11 [484]

Answer:

<h2><em>2(3s-14)</em></h2>

Step-by-step explanation:

Given the angles ∠ABF=8s-6, ∠ABE = 2(s + 11), we are to find the angle ∠EBF. The following expression is true for the three angles;

∠ABF = ∠ABE + ∠EBF

Substituting the given angles into the equation to get the unknown;

8s-6 = 2(s + 11)+ ∠EBF

open the parenthesis

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∠EBF = 8s-6-2s-22

collect the like terms

∠EBF = 8s-2s-22-6

∠EBF = 6s-28

factor out the common multiple

∠EBF = 2(3s-14)

<em></em>

<em>Hence the measure of angle ∠EBF is 2(3s-14)</em>

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77julia77 [94]

Answer

Step-by-step explanation:

i really need help with it

4 0
3 years ago
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