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Basile [38]
3 years ago
15

97. Find the value of y in the relation y = 3x2, when x = 3."1 point​

Mathematics
2 answers:
Brut [27]3 years ago
6 0

Answer:

y = 27

Step-by-step explanation:

Given

y = 3x² ← substitute x = 3

y = 3(3)² = 3(9) = 27

meriva3 years ago
4 0

Answer:

27

Step-by-step explanation:

Given,

x = 3

To find : y = ?

y = 3x^2

= 3 ( 3 )^2

= 3 ( 9 )

y = 27

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PLS HELP PLS ASAP ILL GIVE BRAINLKEST THANKS
Umnica [9.8K]

Answer:

1/2

Step-by-step explanation:

When you analyze the graph for your slope, you RISE over RUN meaning you go up/down first and then left/right next.

I got 1/2 because RISE over RUN is written the same (or is the same) as Y over X

2/4 = 1/2

3/6 = 1/2

4/8 = 1/2

5/10 = 1/2

therefore your slop must be 1/2!

hope this helpsss

4 0
2 years ago
Read 2 more answers
Mary has $2,300. She has decided that she will withdraw a fixed whole-dollar amount of money every month of the year. The fixed
Brrunno [24]

Given : Mary has $2300

Given : Mary decides to withdraw a fixed amount of money every month of the Year.

I'm Solving this Question by Verification of the Given Options

Let us Assume, She Withdraws a fixed amount of $190 every Month

⇒ The Amount she has withdrawn in a year = (190 × 12) = $2280

⇒ The Amount left over will be : (2300 - 2280) = $20

But, we can see that there is no $20 among the 2nd Blank Options. So, This Fixed amount of money cannot be the Answer.

Let us Assume, She Withdraws a fixed amount of $181 every Month

⇒ The Amount she has withdrawn in a year = (181 × 12) = $2172

⇒ The Amount left over will be : (2300 - 2172) = $128

But, we can see that there is no $128 among the 2nd Blank Options. So, This Fixed amount of money cannot be the Answer.

Let us Assume, She Withdraws a fixed amount of $180 every Month

⇒ The Amount she has withdrawn in a year = (180 × 12) = $2160

⇒ The Amount left over will be : (2300 - 2160) = $140

But, we can see that there is no $140 among the 2nd Blank Options. So, This Fixed amount of money cannot be the Answer.

Let us Assume, She Withdraws a fixed amount of $191 every Month

⇒ The Amount she has withdrawn in a year = (191 × 12) = $2292

⇒ The Amount left over will be : (2300 - 2292) = $8

We can see that there is a $8 among the 2nd Blank Options. So, This Fixed amount of money is the Answer.

The Fixed whole-dollar amount of money she takes from her account every month is $191 and she'll have 8 left over.

First Blank : $191

Second Blank : $8

4 0
3 years ago
Solve for x. Show work<br><br><br> 10-1/2x = 6 + 3x
Vikki [24]
<h3>Answer:</h3>

x =  \frac{8}{7}

<h3>Step-by-step explanation:</h3>

10 -  \frac{1}{2} x = 6 + 3x

20 - x = 12 + 6x

20 - x - 6x = 12 + 6x - 6x

20 - x - 6x = 12

- x - 6x = 12 - 20

- 7x = 12 - 20

- 7x =  - 8

x =  \frac{8}{7}

3 0
3 years ago
Read 2 more answers
If the perimeter of a rectangle is 6x^2-2x+14 and the length is x^2-x+8 what is the measure of the width?
s2008m [1.1K]

Answer:

w = 2x^2-2x+15

Step-by-step explanation:

Since the formula to find the perimeter is P=2l+2w, use this to set up your equation:

6x^2-2x+14 = 2(x^2-x+8) + 2w

Then, distribute the 2 to everything inside the parentheses.

6x^2-2x+14 = 2x^2-2x+16 + 2w

Subtract 2x^2-2x+16 from both sides, leaving you:

4x^2-4x+30 = 2w

Divide 2 from both sides.

2x^2-2x+15

The answer is 2x^2-2x+15

7 0
2 years ago
A data set contains an independent and a dependent variable. Which must be true of the data set if a linear function can be
Rom4ik [11]

When we have dependent and independent variables we will have a linear relationship.

Let x be the independent variable and y be the dependent variable.

To write the  relationship we will have :

y = kx + c

Where k and c are constants.

In the case of a line the constant k is the gradient.

A multiplicative change is a log form and it is given by :

Y = Ck^x

The relationship is not linear but exponential.

The correct answer is thus :

Additive rate of change.

5 0
3 years ago
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