For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation:
Answer:
El cuadrado de la suma de dos números es igual a (a + b) ² = a² + 2ab + b²Un producto notable: es una expresión matemática que conocemos ya el resultado, a pesar de la operación ser sencilla tenemos
Imagine that the class only had 4 students (unrealistic most likely, but small numbers help much better I think)
If we had 4 students and 3 were boys, then 4-3 = 1 girl is in the class. This makes the ratio of boys to girls be 3 to 1. In other words, there are 3 times as many boys compared to girls.
Divide the number of girls (1) over the number of students total (4) to get 1/4 = 0.25 = 25%
<h3>Answer: 25%</h3>
