Answer:
23456789
Step-by-step explanation:

Sum of three consecutive odd integers = 

The values of the three integers.



Let us assume the three consecutive odd integers to be
,
and
.
As per the condition, we have



Now, collect the like terms.






Therefore, the three consecutive odd integers whose sum is
are
,
and
respectively.



⇢ L. H. S. = R. H. S.


Answer:
Step-by-step explanation:
The pattern is easy to see.
Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.
No , the order in which the members of the committee are chosen is not important.
Step-by-step explanation:
Given : The total number of students in the council = 30
The number of students needed to be chosen = 5
The order in which the members of the committee are chosen does not matter.
So we Combinations (If order matters then we use permutations.)
The number of combinations of to select r things of n things = 
So the number of ways a committee of 5 students can be chosen from a student council of 30 students=

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.
Answer:
A. 85
Step-by-step explanation: