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irina [24]
3 years ago
11

30 PTS!!! ANYONE GOOD AT MATH PLS HELP!

Mathematics
1 answer:
siniylev [52]3 years ago
8 0

Answer:

\frac{2}{\sqrt{5} }

Step-by-step explanation:

To solve this, all we need to do is draw a triangle.  

From the arctan(2) we can deduce that tan(x)=\frac{2}{1}

From that, we can draw our triangle as we know that tan(x) is the opposite side over the adjacent side. Attached is that triangle. Through the Pythagorean Theorem, we can find that the hypotenuse of this right triangle is  \sqrt{5}

Now all we need to do is take the sin of this triangle, which is the opposite side over the hypotenuse

This gives us the value of \frac{2}{\sqrt{5} } which is our answer.

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In ΔVWX, the measure of ∠X=90°, XW = 36, WV = 85, and VX = 77. What ratio represents the sine of ∠W?
eimsori [14]

<u>Given</u>:

In ΔVWX, the measure of ∠X=90°, XW = 36, WV = 85, and VX = 77.

We need to determine the ratio that represents the sine of ∠W

<u>Ratio of sin of ∠W:</u>

The ratio of sin of ∠W can be determined using the trigonometric ratios.

The ratio of sin \ \theta is given by

sin \ \theta=\frac{opp}{hyp}

From the attached figure, the opposite side of ∠W is XV and the hypotenuse of ∠W is WV.

Hence, substituting in the above ratio, we get;

sin \ W=\frac{XV}{WV}

Substituting the values, we get;

sin \ W=\frac{77}{85}

Thus, the ratio of sine of ∠W is sin \ W=\frac{77}{85}

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3 years ago
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Gre4nikov [31]
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6 0
2 years ago
Juan and his little brother Miguel ran around a circular track together. Juan ran on the inner track, which has a radius of 30 f
eduard

Answer:

80pi-60pi

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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