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3 years ago

30 PTS!!! ANYONE GOOD AT MATH PLS HELP!

Mathematics

1 answer:

siniylev [52]3 years ago

8 0

Answer:

$\frac{2}{\sqrt{5} }$

Step-by-step explanation:

To solve this, all we need to do is draw a triangle.

From the $arctan(2)$ we can deduce that $tan(x)=\frac{2}{1}$

From that, we can draw our triangle as we know that tan(x) is the opposite side over the adjacent side. Attached is that triangle. Through the Pythagorean Theorem, we can find that the hypotenuse of this right triangle is $\sqrt{5}$

Now all we need to do is take the sin of this triangle, which is the opposite side over the hypotenuse

This gives us the value of $\frac{2}{\sqrt{5} }$ which is our answer.

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Bir satıcı sattığı her üründen satış fiyatının 2/9'u kadar kar etmektedir. Bu satıcı 1800 liraya sattığı bir televizyondan kaç l

drek231 [11]

Answer:

400 lira

Step-by-step explanation:

Yukarıdaki sorudan şunu söyleriz: Bir satıcı, sattığı her ürün için satış fiyatının 2 / 9'u kadar kar eder.

Dolayısıyla 1800 liraya televizyon satarsa o televizyondan elde ettiği kâr şöyle hesaplanır:

2/9 × 1800 lira

= 400 lira

6 0

2 years ago

Help me with 2 and 4

Setler79 [48]

Answer:

I only have number 2 but it's C

Step-by-step explanation:

You have to multiply 18.25 3 times since volume of cube is length * width * height

7 0

3 years ago

Read 2 more answers

There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=

yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = $\frac{12P4}{12^{4} }$

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = $\frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }$

P(X=2) = 0.401

P(X=3) = $\frac{4C3 * 12P2}{12^{4} }$

P(x=3) = 0.025

P(X=4) = $\frac{12}{12^{4} }$

P(X=4) = 0.001

Mean, $\mu = \sum xP(x)$

$\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879$

Standard deviation, $SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}$

SD = 1.033

4 0

3 years ago

Caroline bought 20 shares of stock at 101/2, and after 10 months the value of the stocks was 111/4. If Caroline were to sell all

SashulF [63]

The correct answer would be C. $15.

Hope helps

8 0

3 years ago

Why do you think a removable discontinuity (hole) doesn't produce an asymptote on the graph of a polynomial function, even thoug

Monica [59]

Because removable discontituity means that the limit of the function at that point has a finite value, and then you define the value of the function as that valu (the limit value).

An asymptote means that the limit of the function goes to positive or negative infinity.

You cannot meet both conditions, finite and infinity limit at the same time.

8 0

3 years ago