Okay so the answer would be D
I don't know if you know any of this but I'm gonna do my best to explain it to you
So when you have coordinates, lets say ( 3,2) Your three is going to be on your x- axis and the 2 on the y-axis. (the x goes straight across, the y is up and down) When graphing you would count over right 3 on the x and the once you hit that you would go up 2, that is where your point goes. Same with negative if you had (-3,2) you would go left ( since it is negative) 3 and up 2. The way I figured your question out was I just put in all the coordinates and if one of them wasn't on the line, it isn't it. D has all its coordinates on the line. It takes a little to understand where the negatives and positives are on the graph and which way to go but just practice, it becomes fun after a while
I'm sorry if that didn't make much sense, if you were right here i could show you easier but I hope it helps somehow :)
Answer:
Side BC= √5, AB = 2√5, altitude BH = 2
Step-by-step explanation:
In the figure attached let the side BH = h , AC = x , AB = y
We have to find the missing lengths of AB, AC, and BH.
Given sides are AH =4 and CH = 1
In ΔABC ⇒ x²+y²=5²
x²+y²=25------(1)
In ΔHBC ⇒ h² = x²-1² = (x²-1) ( Pythagoras theorem)
In ΔABH ⇒ h² = y²-16 ( Pythagoras theorem)
So h² = x²-1 = y²-16
x²-y² = 1-16 = -15------(2)
By addition of equation 1 and 2.
(x²+y²)+(x²-y²) = 25-15
2x² = 10
x² = 5 ⇒ x = √5
By putting the value of x in equation 1.
5 + y² = 25
y² =25-5 = 20
y = √20 = 2√5
Therefore side BH = h = √(x²-1) = √(5-1) = √4 = 2
100%=$34,50
1%=0,345
6,5*0,345=$2,2425
Hello,
Answer C
y=2x-3.5==>2x-7=3.5 (1)
x-2y=-14 (2)
(1)-2*(2)==>3y=28+3.5 ==>y=31.5/3==>y=10.5
x=-14+2*10.5==>x=7
sol={(7,10.5)}