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denis-greek [22]
1 year ago
9

Select the recursive and explicit formula for the Arnold family 2 answers

Mathematics
1 answer:
MariettaO [177]1 year ago
7 0

Answer: The first and last options are correct

Explanation:

The recursive formula is written in terms of the previous term of the sequence. From the information given,

the Arnold's are going to save a nickel on the first day of the month and double the amount each day of the month. Thus, the recursive formula would be

A(n)\text{ = a}_{n\text{ - 1}}\text{ }\times\text{ 2}

where

an - 1 defines a previous term

To write the explicit formula, we would apply the formula for finding the nth term of an arithmetic sequence which is expressed as

An = ar^(n - 1)

where

a is the first term of the sequence

n is the number of terms

r is the common ratio between consecutive terms

Thus,

r = 2 because the amount is doubling each day

n = number of days

a = value of 1 nickel = $0.05

By substituting these values into the formula,

the explicit formula is

A(n) = 0.05(2)^n - 1

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Which system of linear inequalities has the point (3, –2) in its solution set? y less-than negative 3. y less-than-or-equal-to t
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Answer:

y > -3  and  y \geq \frac{2}{3}x- 4

Step-by-step explanation:

<u>The complete question is</u>

Which system of linear inequalities has the point (3,-2) in its solution set?

A.

y < -3

y ≤ 2/3x - 4

B.

y > -3

y ≥ 2/3x - 4

C.

y < -3

y ≥ 2/3x - 4

D.

y > -2

y ≤ 2/3x - 4

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<em>Verify each case</em>

Case A) we have

y < -3 ----> inequality A

y \leq \frac{2}{3}x- 4 ----> inequality B

Substitute the value of x and  y of the point (3,-2) in both inequalities and then compare the results

Inequality A

-2< -3 ----> is not true

therefore

The ordered pair is not a solution of the system A

Case B) we have

y > -3 ----> inequality A

y \geq \frac{2}{3}x- 4 ----> inequality B

Substitute the value of x and  y of the point (3,-2) in both inequalities and then compare the results

Inequality A

-2< -3 ----> is true

Inequality B

-2 \geq \frac{2}{3} (3)-4

-2\geq -2 ----> is true

therefore

The ordered pair is a solution of the system B

Case C) we have

y< -3----> inequality A

y \geq \frac{2}{3}x- 4 ----> inequality B

Substitute the value of x and  y of the point (3,-2) in both inequalities and then compare the results

Inequality A

-2< -3  ----> is not true

therefore

The ordered pair is not a solution of the system C

Case D) we have

y > -2 ----> inequality A

y \leq \frac{2}{3}x- 4 ----> inequality B

Substitute the value of x and y of the point (3,-2) in both inequalities and then compare the results

Inequality A

-2> -2 ----> is not true

therefore

The ordered pair is not a solution of the system D

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