The equivalent equation of the quadratic equation (x² – 1)² – 11(x² – 1) + 24 = 0 is u² - 11² + 24 = 0
<h3>How to determine the equivalent equation?</h3>
The equation is given as:
(x² – 1)² – 11(x² – 1) + 24 = 0
Let u = x² - 1
So, we have:
u² - 11² + 24 = 0
Hence, the equivalent equation of the quadratic equation (x² – 1)² – 11(x² – 1) + 24 = 0 is u² - 11² + 24 = 0
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SA=(L*W*2)+(L*H*2)+(W*H*2)
SA=208+80+130
SA=418
It's 418
Answer:
The factored form of this is (x - 7)(x -4)
Step-by-step explanation:
In order to factor quadratic equaitons with a 1 as the first coefficient, we look for two numbers that multiply to the last number (28), but add up to the middle number (-11). To do this, we often list the factors of the last number.
Factors of 28
1, 28
-1, -28
2, 14
-2, -14
4, 7
-4, -7
The numbers -4 and -7 satisfy this requirement and are therefore the numbers we want. Now we stick them into parenthesis along with x terms in the front like this:
(x - 7)(x -4)
And that is the fully factored form.
