PLEASE HELP GEOMETRY!!!

What is the time and space margin that is the distance you can see ahead of your vehicle?

IgorLugansk [536]

The space margin depends on light and weather conditions as well as terrain (road curvature, hills, trees or other obstacles).

The time margin depends on the space margin, your reaction time, and your speed of travel.

You may appear to have a lot of time or space in icy conditions, but that can be an illusion. A collision course on ice will result in a collision, regardless of the time or distance involved.

Insufficient information is provided to be more specific.

5 0

3 years ago

Josh drew ∆ ABC with mm∠A = 40°, m∠B = 60° and m∠ C = 80°. Howard drew ∆ XYZ with m∠Y = 60° and m∠ Z = 80°. What can you say abo

aliya0001 [1]

Answer:

Both of these triangles are congruent.

Step-by-step explanation:

All 3 angle measures of both of the triangles are equivalent and correlate to each other. This makes the triangles congruent.

7 0

3 years ago

Nth Term help please

liberstina [14]

$\bf \begin{array}{|ll|ll} \cline{1-2} term&value\\ \cline{1-2} a_1&3\\[0.8em] a_2&\stackrel{3\cdot 2}{6}\\[0.8em] a_3&\stackrel{6\cdot 2}{12}\\[0.8em] a_4&\stackrel{12\cdot 2}{24}\\[0.8em] a_5&\stackrel{24\cdot 2}{48}\\[0.8em] a_6&\stackrel{48\cdot 2}{96} \\ \cline{1-2} \end{array}$

8 0

3 years ago

In a picture, there are 40 monkeys, and 60% of the monkeys are in the trees.

Zepler [3.9K]

The number of monkeys in the tree are 24.

<h3>What are percentages?</h3>

Percentage is the fraction of an amount expressed as a number out of hundred. The sign used to represent percentages is %.

<h3>How many monkey are in the tree?</h3>

Number of monkeys in the tree = percent x total number of monkeys

60% x 40

0.6 x 40 = 24

To learn more about percentages, please check: brainly.com/question/25764815

6 0

2 years ago

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

$(\left {{20} \atop {2}} \right. )$ $=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

$(\left {{3} \atop {2}} \right. )$ $=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$\frac{3}{190}\\ =0.01579\\=0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

#SPJ4

4 0

1 year ago