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AnnZ [28]
2 years ago
12

Which statement explains whether or not the parallelgrams can be put together so each occupies one-quarter of the area of the ci

rcle without overlapping any other pieces? Check all that apply.
The quadrilaterals can be placed such that each occupies one-quarter of the circle.

The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles.

The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 2 do not form right angles.

The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 3 do not form right angles.

The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.
Mathematics
1 answer:
Ganezh [65]2 years ago
6 0

Answer:B And E

Step-by-step explanation: Just took the test

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0.86 is 3.06 % of what number (Round to the nearest hundredth.)
polet [3.4K]

Answer:

Let the number be x

3.06% = 0.0306

The above statement is written as

0.0306x = 0.86

Divide both sides by 0.0306

x = 0.86/0.0306

<h2>x = 28.10</h2>

Hope this helps you

4 0
3 years ago
Given the system of equations:
uranmaximum [27]

Answer:

x=4

y=2

Step-by-step explanation:

2x+2y=12

x−y=2

​In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

2x+2y=12,x−y=2

To make 2x and x equal, multiply all terms on each side of the first equation by 1 and all terms on each side of the second by 2.

2x+2y=12,2x+2(−1)y=2×2

Simplify.

2x+2y=12,2x−2y=4

Subtract 2x−2y=4 from 2x+2y=12 by subtracting like terms on each side of the equal sign.

2x−2x+2y+2y=12−4

Add 2x to −2x. Terms 2x and −2x cancel out, leaving an equation with only one variable that can be solved.

2y+2y=12−4

Add 2y to 2y.

4y=12−4

Add 12 to −4.

4y=8

Divide both sides by 4.

y=2

Substitute 2 for y in x−y=2. Because the resulting equation contains only one variable, you can solve for x directly.

x−2=2

Add 2 to both sides of the equation.

x=4

The system is now solved.

x=4,y=2

Correct choice is B) x=4.

8 0
2 years ago
Read 2 more answers
Help me with the last part at the bottom please it says x =
lukranit [14]

Answer:

Step-by-step explanation:

x = 0.8 + 0.2y

7 0
3 years ago
Among all pairs of numbers whose sum is 12 , find a pair whose product is as large as possible. What is the maximum product? Sho
kolezko [41]

Answer:

We can only take positive number , Because negative is always smaller than positive.

We can take ,

6 + 6 = 12 .

6 x 6 = 36.

Where both are largest numbers possible.

Thus, the answer is 36.

7 0
3 years ago
125.7 - (-1.82) = 1.439<br> True<br> False
sdas [7]
We automatically know that this is false because if we take the whole numbers in front of the numbers and do the operation
125-(-1)=1
125+1=1
126=1
very far
therefor since the decimals are less than 1 and the distance is more than 3, we conclude that this is false
7 0
3 years ago
Read 2 more answers
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