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nikklg [1K]
3 years ago
12

What value of x is in the solution set of -5x – 15 > 10 + 20x? -2 -1 0 1

Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer: x < -1

Step-by-step explanation:

-5x-15>10+20x

-5x-15-20x>10'-25x-15>10

-25x-15>10

-25x>10+15

-25x>25

x < 25 / -25

=

x < -1

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Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

8 0
3 years ago
Whats the least common denominator of 9, 13, and 20
aliya0001 [1]

Answer:

13 = 13  

20 = 2^2 • 5  

9 = 32

Prime Factor   Number 13   Number 20   Number 9    L.C.M  

   2                         0                        2                     0               2

   3                          0                        0                     2               2                                                  

   5                          0                         1                     0                  1  

 

   13                         1                         0                    0                   1

6 0
2 years ago
A rectangular parking lot is 75 feet wide and 150 feet long. The owner wants to increase the width by 100 feet. What is the appr
Trava [24]

The <em>approximate increase</em> in Area of the parking lot is about 133%

Area of a rectangle = Length × width

<u>Initial Area of parking lot</u> :

  • 75 feets × 150 feets = 11250 ft²

<u>New Area of parking lot</u> :

Width = 75 + 100 = 175 feets

Length = 150 feets

Area = 175 × 150 = 26250 ft²

<u>Percentage increase in </u><u>Area</u><u> </u><u>of lot</u> :

((16250 - 11250) / initial Area) × 100%

(15000 / 11250) × 100% = 133.33%

Therefore, the <em>approximate increase</em> on area of lot is 133%

Learn more : brainly.com/question/18109354

5 0
2 years ago
Pretty PLEASE can you help me solve this? I know that the answer is not (-5, -3), if that helps.
Naddik [55]

<em>Please refer to the attachment for the answer and explanation. Hope it helps!!</em>

7 0
2 years ago
8x+11=14-1x how does it work
Alenkinab [10]

Answer:

x = 1/3

Step-by-step explanation:

Step 1: Write equation

8x + 11 = 14 - 1x

Step 2: Solve for <em>x</em>

  1. Simplify: 8x + 11 = 14 - x
  2. Add x to both sides: 9x + 11 = 14
  3. Subtract 11 on both sides: 9x = 3
  4. Divide both sides by 9: x = 3/9
  5. Simplify: x = 1/3

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

8(1/3) + 11 = 14 - 1(1/3)

8/3 + 11 = 14 - 1/3

41/3 = 41/3

3 0
2 years ago
Read 2 more answers
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