0=-10 this is not possible so the answer is no solution
Answer:
The period when its more than halfway
= 2 < t ≤ 2.83 seconds ( to nearest hundredth).
Step-by-step explanation:
When is is halfway down the ramp d = 3920/2 = 1960 cm, so:
1960 = 490 t^2
t^2 = 1960/490 = 4
t = 2 seconds.
When it reaches the bottom d = 3920 :
t^2 = 3920/490 = 8
t = 2.83 seconds.
The answer should be a segment. have a great day :)))
Answer:
Velocity of jet in still air is 970 miles per hour and velocity of wind is 210 miles per hour.
Step-by-step explanation:
Jet's velocity against wind is
3040/4 = 760 miles per hour and flying with wind it is
8260/7 = 1180 miles per hour.
Let the velocity of jet in still air be x miles per hour and velocity of wind be y miles per hour.
As such its velocity against wind is x − y and with wind is x + y and therefore
x − y = 760 and x + y = 1180
Adding the two 2 x = 1940 and x = 970 and y = 1180 − 970 = 210
Hence velocity of jet in still air is 970 miles per hour and velocity of wind is
210 miles per hour.
Actual Answer:
https://socratic.org/questions/flying-against-the-wind-a-jet-travels-3040-miles-in-4-hours-flying-with-the-wind
