![\displaystyle\int_2^8g(x)\,\mathrm dx=12](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_2%5E8g%28x%29%5C%2C%5Cmathrm%20dx%3D12)
![\displaystyle\int_6^8g(x)\,\mathrm dx=-3](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_6%5E8g%28x%29%5C%2C%5Cmathrm%20dx%3D-3)
Use the fact that integrals are additive on their intervals. Mathematically, if
, then
![\displaystyle\int_a^bg(x)\,\mathrm dx=\int_a^cg(x)\,\mathrm dx+\int_c^bg(x)\,\mathrm dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_a%5Ebg%28x%29%5C%2C%5Cmathrm%20dx%3D%5Cint_a%5Ecg%28x%29%5C%2C%5Cmathrm%20dx%2B%5Cint_c%5Ebg%28x%29%5C%2C%5Cmathrm%20dx)
So we have
![\displaystyle2\int_2^6g(x)\,\mathrm dx=2\left(\int_2^8g(x)\,\mathrm dx-\int_6^8g(x)\,\mathrm dx\right)=2(12-(-3))=30](https://tex.z-dn.net/?f=%5Cdisplaystyle2%5Cint_2%5E6g%28x%29%5C%2C%5Cmathrm%20dx%3D2%5Cleft%28%5Cint_2%5E8g%28x%29%5C%2C%5Cmathrm%20dx-%5Cint_6%5E8g%28x%29%5C%2C%5Cmathrm%20dx%5Cright%29%3D2%2812-%28-3%29%29%3D30)
Answer:
10 if distance from origin
Step-by-step explanation:
Step-by-step explanation:
she needs to swap 5.2 for 5.02
since 5.02 is smaller than 5.2
Answer:
x = 3
Step-by-step explanation:
In a 30-60-90 triangle the side between 60 and 90 degree angle is a, the side between 30 and 90 degree angle is a√3, and the hypotenuse is 2*a.
Given that the side that is supposed to be a is currently √3, we know that the missing side x must be:
a√3 (We know that a, in this case, is √3, so substitute)
x = (√3) * (√3)
x = 3
Answer:
Please see attachment
Step-by-step explanation:
Please see attachment