Question

What is the range of the function f(x) = 3x2 + 6x – 8?

Answer 1

Answer:

Range → {y| y ≥ -11}

Step-by-step explanation:

Range of a function is the set of of y-values.

Given function is,

f(x) = 2x² + 6x - 8

By converting this equation into vertex form,

f(x) = $3(x^2+2x-\frac{8}{3})$

     = $3(x^2+2x+1-1-\frac{8}{3})$

     = $3[(x+1)^2-\frac{11}{3}]$

     = $3(x+1)^2-11$

Vertex of the parabola → (-1, -11)

Therefore, range of the function will be → y ≥ -11