Answer:
The statement is true.
Explanation:
The myocardium is the muscle tissue of the heart, a muscle responsible for pumping blood through the circulatory system through contraction. It receives a part of the large volume of blood that passes through the atria and ventricles. A system of arteries and veins (coronary circulation) provides the myocardium with oxygen-rich blood and allows the return of venous or oxygen-poor blood to the right atrium. The right coronary artery and the left coronary artery are the branches of the aorta responsible for the blood supply.
<h3><u>Answer;</u></h3>
Label A; Mitochondria.
Label B; Nucleus.
Label C; Golgi apparatus.
Label D; Rough endoplasmic reticulum
<h3><u>Explanation;</u></h3>
- All the above are various organelles in a eukaryotic cells each carrying different cellular activity to enhance the functioning of a cell.
Label A; Mitochondria.
- <u>Mitochondria</u> is the powerhouse of the cell which converts glucose to energy rich molecules of ATP, through the process of cellular respiration.
Label B; Nucleus.
- <u>Nucleus</u> contains the genetic material or DNA, RNA , nucleolus, chromatin fibres and proteins. It contains the chromosomes which control the hereditary characteristics.It also regulates all the activities of the cell.
Label C; Golgi apparatus.
- <u>Golgi apparatus;</u> they are also called Golgi bodies. They function in modifying, sorting and packaging of proteins for secretion. They are also involved in the transport of lipids around the cell, and the creation of lysosomes.
Label D; Rough endoplasmic reticulum
- <u>The rough endoplasmic reticulum</u> provides surface for protein synthesis. It is also used to transport cellular contents from one cell to another.
- The risbosomes attached on the rough endoplasmic reticulum are resposible for the protein synthesis through the process of translation.
Answer:
Explanation:
All hydrocarbons are apolar
They contain covalent bond(s)
Hydrocarbons contain only carbon and hydrogen atoms
Hyrdrocarbons held by london forces
True answer is d
Smaller cube (1 cm X 1 cm X 1 cm)
<span>The surface area of one side = 1 cm X 1 cm = 1 <span>cm2</span></span>
<span>There are 6 sides, total SA = 6 X 1 <span>cm2</span> = 6 <span>cm2</span></span>
<span>Volume = 1 cm X 1 cm X 1 cm = 1 cubic cm (1 <span>cm3</span>)</span>
<span>Surface to Volume Ratio = 6 <span>cm2</span>/1 <span>cm3</span> = 6 <span>cm2/cm3</span></span>
Larger cube (6 cm X 6 cm X 6 cm)
<span>The surface area of one side = 6 cm X 6 cm = 36 <span>cm2</span></span>
<span>There are 6 sides, the total SA = 6 X 36 <span>cm2</span> = 216 <span>cm2</span></span>
<span>Volume = 6 cm X 6 cm X 6 cm = 216 <span>cm3</span></span>
<span>Surface to Volume Ratio = 216 <span>cm2</span>/216 <span>cm3</span> = 1 <span>cm2/cm3</span></span>
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