Answer:
the amount of each charge and the distance between them. ... Coulomb's law states the the electric force between two charges is proportional to the product of the two charges and inversally proportional to the square distance that separates their centers.
Answer:
Explanation:
We shall consider a Gaussian surface inside the insulation in the form of curved wall of a cylinder having radius equal to 3mm and unit length , length being parallel to the axis of wire .
Charge inside the cylinder = 250 x 10⁻⁹ C .
Let E be electric field at the curved surface , perpendicular to surface .
Total electric flux coming out of curved surface
= 2π r x 1 x E
= 2 x 3.14 x 3 x 10⁻³ E
According to Gauss's theorem , total flux coming out
= charge inside / ε ( 250 x 10⁻⁹C charge will lie inside cylinder )
= 250 x 10⁻⁹ / 2.5 x 8.85 x 10⁻¹² ( ε = 2.5 ε₀ = 2.5 x 8.85 x 10⁻¹² )
= 11.3 x 10³ weber .
so ,
2 x 3.14 x 3 x 10⁻³ E = 11.3 x 10³
E = 11.3 x 10³ / 2 x 3.14 x 3 x 10⁻³
= .599 x 10⁶ N /C .
A<span>. speed= distance/ time
s= 4</span><span>.6m/s
d=60m
4</span><span>.6= 60/t
</span>4.6t= 60
t= 13.04 seconds
b. acceleration= (the change in velocity/speed)/(time) this is the same as a=Δv/t<span>
a= unkown
</span>Δv= (final speed - initial speed) = 3.1m/s - 4.6m/s= -1.5m/s
t=3 seconds
a=Δv/t= -1.5/3= -0.5m/s²
answer: the soccer player decelerated by 0.5m/s². This means his speed is decreasing by 0.5m/s². We know it is decreasing because the answer is negative.
c. list given information:
final velocity/speed(FS)= 0m/s
initial velocity/speed(IS)= 4m/s
distance(d)= 2m
time(t)= UNKOWN
acceleration(a)= UNKOWN
(side note: velocity and speed are almost the same thing. The difference between the two words is that velocity usually has a direction and can be negative. Speed cannot be negative. If your problems use the word "speed" I would recommend you continue to use the word "speed" as well. I wanted to clarify this so that you didn't think I was saying to divide velocity by speed.)
Equation: (final speed²)= (inital speed²)+ 2(distance)(acceleration)
FS²=IS²+2da
(0²)= (4²)+ 2(2)a
0=16+4a
-4a=16
a= -4m/s²
answer: The deceleration(decreasing acceleration) is 4m/s². This is because the speed was changing at a rate of negative 4 meters per second squared until reaching a final speed of 0m/s.
d. List given information:
Initial speed: 0m/s (we know he started from "rest" which means his IS was 0)
Final speed: UNKNOWN
time= 1.5seconds
distance= UNKOWN
acceleration= 3.1m/s²
Equation: distance= (initial speed * t) + ((1/2)*(acceleration)*(time²)
d= (IS)t + (1/2)at²
d= (0)(1.5)+ (1/2)(3.1)(1.5²)
d= 0 + 3.4785
d≈3.5 meters
Any confusion or questions? Hope this helped!