Explanation:
the object with the higher temperature has greater thermal energy
So the answer is
the stick of butter with less thermal energy.
Hope it will help :)
Comets are divided into two types. Long-period comets are the comets that take more than two hundred years to finish an orbit throughout the Sun originate from the Oort Cloud.
<u>Explanation:</u>
- The Oort Cloud has sufficient distance apart of the Sun than the Kuiper Belt, it seems that the Oort Cloud objects were made closer to the Sun than the Kuiper Belt things.
- Long-period comets have highly eccentric orbits.
- The Oort cloud is considered to own a large range commencing from among 2,000 and 5,000 AU to 50,000 AU.
- The chemical makeup of long-period and short-period comets is quite alike.
Answer:
, assuming that the gravitational field strength is
.
Explanation:
Notice that both the speed and the direction of motion of this block are constant. In other words, the velocity of this block is constant.
By Newton's Second Law, the net force on this block would be
. External forces on this block should be balanced. Thus, the magnitude of the (downward) weight of this block should be equal to the magnitude of the (upward) force that the boy applies on this block.
Let
denote the mass of this block. It is given that
. The weight of this block would be:
.
Hence, the force that the boy applies on this block would be upward with a magnitude of
.
The mechanical work that a force did is equal to the product of:
- the magnitude of the force, and
- the displacement of the object in the direction of the force.
The displacement of this block (upward by
) is in the same direction as the (upward) force that this boy had applied. Thus, the work that this boy had done would be the product of:
- the magnitude of the force that this boy exerted,
, and - the displacement of this block in the direction,
.
.
Accelerator pedal and brake pedal
Answer:
a.![10.2mm/s^2](https://tex.z-dn.net/?f=10.2mm%2Fs%5E2)
b.25.2 s
Explanation:
We are given that
Initial velocity=0
Tangential acceleration=![a_t=10mm/s^2](https://tex.z-dn.net/?f=a_t%3D10mm%2Fs%5E2)
![r=0.8 m=0.8\times 10^3 mm=800mm](https://tex.z-dn.net/?f=r%3D0.8%20m%3D0.8%5Ctimes%2010%5E3%20mm%3D800mm)
By using ![1 m=10^3 mm](https://tex.z-dn.net/?f=1%20m%3D10%5E3%20mm)
a.t=4 s
![a_t=\frac{v-u}{t}](https://tex.z-dn.net/?f=a_t%3D%5Cfrac%7Bv-u%7D%7Bt%7D)
Using the formula
![10=\frac{v}{4}](https://tex.z-dn.net/?f=10%3D%5Cfrac%7Bv%7D%7B4%7D)
![v=4\times 10=40mm/s](https://tex.z-dn.net/?f=v%3D4%5Ctimes%2010%3D40mm%2Fs)
Normal acceleration=![a_N=\frac{v^2}{r}](https://tex.z-dn.net/?f=a_N%3D%5Cfrac%7Bv%5E2%7D%7Br%7D)
Substitute the values
Normal acceleration=![a_N=\frac{(40)^2}{800}=2mm/s^2](https://tex.z-dn.net/?f=a_N%3D%5Cfrac%7B%2840%29%5E2%7D%7B800%7D%3D2mm%2Fs%5E2)
Magnitude of acceleration=a=![\sqrt{a^2_t+a^2_N}](https://tex.z-dn.net/?f=%5Csqrt%7Ba%5E2_t%2Ba%5E2_N%7D)
Using the formula
Magnitude of acceleration=a![=\sqrt{(10)^2+(2)^2}=10.2mm/s^2](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%2810%29%5E2%2B%282%29%5E2%7D%3D10.2mm%2Fs%5E2)
Magnitude of acceleration=a=![10.2mm/s^2](https://tex.z-dn.net/?f=10.2mm%2Fs%5E2)
b.Magnitude of acceleration=a=![80mm/s^2](https://tex.z-dn.net/?f=80mm%2Fs%5E2)
![a^2=a^2_t+a^2_N](https://tex.z-dn.net/?f=a%5E2%3Da%5E2_t%2Ba%5E2_N)
Substitute the values
![(80)^2=(10)^2+a^2_N](https://tex.z-dn.net/?f=%2880%29%5E2%3D%2810%29%5E2%2Ba%5E2_N)
![6400=100+a^2_N](https://tex.z-dn.net/?f=6400%3D100%2Ba%5E2_N)
![a^2_N=6400-100=6300](https://tex.z-dn.net/?f=a%5E2_N%3D6400-100%3D6300)
![a_N=\frac{a^2_t t^2}{r}](https://tex.z-dn.net/?f=a_N%3D%5Cfrac%7Ba%5E2_t%20t%5E2%7D%7Br%7D)
![\sqrt{6300}=\frac{(10)^2t^2}{800}](https://tex.z-dn.net/?f=%5Csqrt%7B6300%7D%3D%5Cfrac%7B%2810%29%5E2t%5E2%7D%7B800%7D)
![t^2=\frac{\sqrt{6300}\times 800}{100}](https://tex.z-dn.net/?f=t%5E2%3D%5Cfrac%7B%5Csqrt%7B6300%7D%5Ctimes%20800%7D%7B100%7D)
![t=\sqrt{\frac{\sqrt{6300}\times 800}{100}}](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B%5Cfrac%7B%5Csqrt%7B6300%7D%5Ctimes%20800%7D%7B100%7D%7D)
![t=25.2 s](https://tex.z-dn.net/?f=t%3D25.2%20s)
Hence, the time for the magnitude of the acceleration to be
=25.2 s