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3 years ago

Please answer this correctly

Mathematics

1 answer:

marusya05 [52]3 years ago

4 0

Answer:

662

Step-by-step explanation:

l x w

10x41

6x22

8x15

662

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Solve the following equation for x: 5x + 3y = 15.

Blizzard [7]

Answer:

x = negative three fifthsy + 3

Step-by-step explanation:

5x + 3y = 15

Subtract 3y from both the sides,

5x = 15 - 3y

Divide by 5 on both sides,

x = -3y/5 + 15/5

x = -3y/5 + 3

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3 years ago

Hunter installed tiles on a floor with a length of 12 feet and a width of 9 feet in 712 hours. how many square feet of tiles can

grandymaker [24]

He can install 0.2 and .2 is rounded im sure

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3 years ago

A chemist needs to create a 50% HCl solution. (HCl is hydrochloric acid. A "50% HCl solution" contains 50% HCl and the other 50%

lorasvet [3.4K]

25/100=30/x x=120 (30+70y)/(120+100y)=50/100 100y=?

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3 years ago

Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box

pantera1 [17]

To find the z-score for a weight of 196 oz., use

$z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2$

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0

3 years ago

Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.

FrozenT [24]

You have shared the situation (problem), except for the directions: What are you supposed to do here? I can only make a educated guesses. See below:

Note that if   <span>ax^2+bx+5=0 then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers. If this is the case, then the discriminant, b^2 - 4(a)(c), must be positive. Since c = 5,

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

- b plus sqrt( b^2 - 20a )
d =  ------------------------------------
2a

and

</span> - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b." Before going into that, however, I'm asking you to share the rest of the problem statement. What, specificallyi, were you asked to do here?

7 0

3 years ago