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IgorLugansk [536]
3 years ago
12

49–2ax –a^2–x^2 factor

Mathematics
1 answer:
vampirchik [111]3 years ago
4 0

49–2ax –a^2–x^2

Extract the negative sign

= 49 - (a^2 +2ax +x^2)

Factor using a^2 + 2ab + b^2 = (a+b)^2

= 49 - (a+x)^2

Factor using a^2 - b^2 = (a-b)(a+b)

= ( 7- (a + x)) * (7 + (a + x))

= ( 7- a - x) * (7 + a + x)

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Answer:

See below.

Step-by-step explanation:

It can really help to think when you see |expression| that it means the distance from expression to zero.

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(c)  |y - 8| > 11 means that the distance from y - 8 to 0 is more than 11 units.  That puts  y - 8 in one of two places:  left of -11 or right of 11.

y-8 < -11 \text{ or } y-8 > 11\\\\y < -3 \text{ or } y > 19

(g)  |3x-1| \ge 18 means that the distance from 3x - 1 to 0 is more than (or equal to)  18.  Another way to say it is, 3x - 1 is farther from 0 than 18 units.  That puts  3x - 1 in one of two places:  to the left of -18 or to the right of 18.

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Step-by-step explanation:

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