We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
Since all you’re saying is evaluate ∫12–2
I’m assuming the answer would be 1/(1+x)(1-x)
You have to foil out the problem
(2x+8)(2x+8)
4x^2+16x+16x+64
4x^2+32x+64
What is proportional?
Can you copy and paste the question or link the website?
I ***POSSIBLY*** can TRY to help you
Answer:
48cm
Step-by-step explanation:
take width of rectangle to be=xcm
Length will be 3x
Area of rectangle=length × width
A=3x × x =3x²
3x²=108
x²=108/3=36
x²=36
x=√36=6cm
substitute
lenth=3x=3×6=18
width=x=6cm
perimeter=2l+2w
p=2×18 + 2×6
p=36+12=48cm