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4 years ago

Find the volume10ft, 15ft, 9ft

Mathematics

2 answers:

sammy [17]4 years ago

7 0

Answer:

Step-by-step explanation:

If this is a cube

The volume = Height x Width x Depth

V = 10 x 15 x 9 = 1350 cu. ft.

Trava [24]4 years ago

7 0

Answer:

1350 cubic feet

Step-by-step explanation:

Just multiply all numbers and get the answer! Easy!

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How many solutions does two lines with the same slope and the same y-intercept have.

schepotkina [342]

Answer:one

Step-by-step explanation:because

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3 years ago

Factor Completely 14bx^2-7x^3-4b+2x

Mnenie [13.5K]

Answer:

=14bx2−7x3−4b+2x

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

Which proportion can be used to find 65% of 90?

ra1l [238]

X 65%
———— = ———-
90 100

1) multiply across
90 • 65 = 5,850

2) divide what’s left over.
5,850 / 100 = 58.5

3 0

3 years ago

Which expressions are equivalent when m = 1 and m = 4?

s344n2d4d5 [400]

Answer:

expression 2

Step-by-step explanation:

<h2><u>Which expressions are equivalent when m = 1 and m = 4?</u></h2>

<h3><u>first expression:</u></h3>

5m -3 and 2m + 5 + m

when m = 1

5(1) - 3 = 2 and 2(1) + 5 + 1 = 8

and m = 4

5(4) -3 =23 and 2(4) + 5 + 4 = 17

<u>expression 1 IS</u><u> NOT EQUIVALENT</u><u> </u>

<h3><u>second expression :</u></h3>

3 m + 4 and m + 4 + 2 m

when m = 1

3 (1) + 4 = 7 and 1 + 4 +2 (1) = 7

and m = 4

3 (4) + 4 = 16 and 4 + 4 +2 (4) = 16

expression 2 <u>IS EQUIVALENT </u>

<h3><u>third expression :</u></h3>

2 m + 7 and 3 m - 3 + m

when m = 1

2(1) + 7 = 9 and 3(1) -3 + 1 = 1

and m = 4

2(4) + 7 = 15 and 3(4) -3 + 4 = 13

expression 3 IS <u>NOT EQUIVALENT</u>

<h3><u>fourth expression :</u></h3>

5 m + 3 and 4 m + 2 + 2 m

when m = 1

5(1)+ 3 = 8 and 4(1) + 2 +2(1) = 8

and m = 4

5(4)+ 3 = 23 and 4(4) + 2 +2(4) = 26

expression 4 is <u>NOT EQUIVALENT </u>

the expression that is <u><em>EXPRESSION 2 </em></u>

8 0

3 years ago

Read 2 more answers

Find the volume10ft, 15ft, 9ft​

Find the volume10ft, 15ft, 9ft