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2 years ago

The height of Mount Everest is 8,848 m and the height of Aconcagua is 6,962 m.

Mathematics

2 answers:

Murljashka [212]2 years ago

6 0

Answer:

B.i think

Step-by-step explanation:

hopethis helps

____ [38]2 years ago

4 0

Answer:

22.6

Step-by-step explanation:

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Which phrase correctly represents the algebraic expression for 22-n?

Harrizon [31]

Answer:

Step-by-step explanation:

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2 years ago

This is a 3 part question, PLEASE HELP ILL GIVE BRAINLY

kaheart [24]

Answer:

Angle of A = 90 degree-62 degree = 28 degree.

Step-by-step explanation:

tan (62) = opposite / adjacent = 10 / a ---> a = 10/tan (62) = 10/ 1.88 = 5.319

cos (62) = a/c --->c = a/cos (62) = 5.319 / 0.47 = 5.3 / 0.47 = 11.3

or another way.

sin (62) = 10 /c ---> c = 10/ sin (62) = 10 / 0.88 = 11.3

So Angle of A = 28 degree.

a = 5. 3

c = 11.3.

please give me brainliest. I hope it help.

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2 years ago

GRAPHING INEQUALITIES

Rudiy27

I don’t know put 2x on the x axis and dot 0 on the y axis

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2 years ago

The expression for the amount of money earned on a savings account compounded quarterly is given by the expression x(1.1)^4t, wh

posledela

Selection D is the equivalent form of the given expression.

_____
The nominal annual interest rate in this problem is 40%. If it were compounded half-yearly, the formula would be x(1.2)^(2t) or x(1.44)^t. Apparently, this problem is more concerned with the equivalent form of the expression than it is with half-yearly compounding.

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2 years ago

15 points!!! GEOMETRY help please!!<br> Questions attached!

dolphi86 [110]

3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

$x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o$

$Answer:\ \boxed{47^o}$

4.
Look at the picture.

Use Pythagorean theorem:

$x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8$

$Used:\ (a+b)^2=a^2+2ab+b^2$

$Answer:\ \boxed{4.8\ units}$

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}$

We have: $OP:\ y=-\dfrac{3}{2}x+b$

Now, we must find the slope of the line perpendicular to the line OP.
We know:

$k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1$

therefore

$-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}$

So. We have the answer! :)

$Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}$

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2 years ago